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May 25, 2015 at 10:36 comment added sl34x Could you please draw-me an equivalent circuit to better understand it? Also: I noticed that \$v_{R_2}=v_1-v_2 - v_{R_1} = v_1 - v_2 - v_1+ v_2 =0 \$. Is this right?
May 25, 2015 at 10:21 history answered Andy aka CC BY-SA 3.0