Timeline for How to convert low voltage (< 0.4V) AC to DC
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Sep 20, 2015 at 11:14 | comment | added | Spehro 'speff' Pefhany | Nice writeup on your project. | |
| Sep 19, 2015 at 9:55 | comment | added | Anc | If you want to see: wikilabomedia | |
| Sep 19, 2015 at 9:53 | comment | added | Anc | Done, and work fine ! : after the what we call the "CI" turbine, we put a transformer 5vac/230Vac for printed circuits, then we put a diodes bridge made with 4 1N5817 Schottky diodes, then we put a 50V/220µF capacitor, and at the end a ruban of LEDs. We turn the turbine at 60 RPM (1 turn per second). The current just after the turbine gives an 1volt AC. The current just after the transformer gives a 30 volts AC. The current just after the diodes bridge gives a not smoothed DC 15 volt. The current after the capacitot gives 15 volt DC totaly planed (a great line). | |
| Jul 31, 2015 at 15:14 | vote | accept | Anc | ||
| Jul 31, 2015 at 14:58 | comment | added | Spehro 'speff' Pefhany | Transformer directly first, transformers don't like DC. | |
| Jul 31, 2015 at 14:54 | comment | added | Anc | We are going to try both solutions: in one hand Schottky diodes bridge; and in the other hand transformer solution. Do we have, first to convert accross the Schottky diodes bridge and then place the transformer, or could we place directly the transformer without any before Schottky diodes bridge ? | |
| Jul 31, 2015 at 14:19 | comment | added | Spehro 'speff' Pefhany | @BrianDrummond What losses are you thinking of? If the source is really high-Z then magnetizing current might be an issue, but transformer internal losses (core and winding I^2R) will be very low at 6% of design flux density (60Hz) and from a few Hz to a few hundred Hz. | |
| Jul 31, 2015 at 13:57 | comment | added | user16324 | 30:1 would probably not be good, it implies scaling impedances by 900:1, at which point the transformer's own losses tend to absorb most of the available power. Diminishing returns probably start between 5 or 10:1. It might also be useful to know the frequency range, and source resistance of the generator. | |
| Jul 31, 2015 at 13:40 | history | answered | Spehro 'speff' Pefhany | CC BY-SA 3.0 |