Timeline for Transistors absolute maximum values
Current License: CC BY-SA 3.0
17 events
when toggle format | what | by | license | comment | |
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Aug 7, 2015 at 8:31 | vote | accept | Vrisk | ||
Aug 6, 2015 at 0:52 | comment | added | Vrisk | @Dave Tweed, . I'm so sorry in my haste I messed I, I fixed it now. I think the current has to flow through the collector to the emitter but it's passing through the base to the emitter. I tried again with a fresh transistors and this happened again (is it because the base emitter if forward biased?) This is not very helpful for logic gate since the output from the emitter becomes the next base but yet transistor logic gates are made. Isthere any way around this? | |
Aug 6, 2015 at 0:40 | history | edited | Vrisk | CC BY-SA 3.0 |
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Aug 6, 2015 at 0:32 | history | edited | Vrisk | CC BY-SA 3.0 |
added 41 characters in body
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Aug 5, 2015 at 16:17 | comment | added | Dave Tweed | OK, I think I might see the problem. Are any of the resistor legs touching any of the metal transistor cases? If so, the transistor will turn on even if the other leg of the resistor is open. | |
Aug 5, 2015 at 16:03 | comment | added | Dave Tweed | Clearly, the schematic does not match the breadboard. Where's the 7806 regulator, the 9V battery, the second transistor? And with the one-transistor circuit you've drawn, why do you think the LED should NOT be lit? | |
Aug 5, 2015 at 15:55 | answer | added | LorenzoDonati4Ukraine-OnStrike | timeline score: 2 | |
Aug 5, 2015 at 15:54 | comment | added | Peter Bennett | Your schematic only shows one transistor - where's the AND gate? | |
Aug 5, 2015 at 15:49 | comment | added | LorenzoDonati4Ukraine-OnStrike | @SpehroPefhany No it's really the other way around! ;-) If you overheat the semiconductor electrons begin to jump out of holes (maybe because it's too hot there :-D ) | |
Aug 5, 2015 at 15:49 | comment | added | Kvegaoro | VCBO collector-base voltage open emitter − 75 V VCEO collector-emitter voltage open base − 40 V VEBO emitter-base voltage open collector − 6 V IC collector current (DC) − 600 mA ICM peak collector current − 800 mA IBM peak base current − 200 mA Ptot total power dissipation Tamb ≤ 25 °C − 500 mW Tstg storage temperature −65 +150 °C Tj junction temperature − 150 °C Tamb ambient temperature −65 +150 °C Those are the stated max values on the data sheet, which one of this max values do you think you are running at or exceeding?? because I do not think you are exceeding any | |
Aug 5, 2015 at 15:43 | comment | added | Vrisk | @Dave Tweed , Alright , schematics added | |
Aug 5, 2015 at 15:41 | history | edited | Vrisk | CC BY-SA 3.0 |
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Aug 5, 2015 at 15:32 | comment | added | Dave Tweed | We still can't see how the components are connected. Use the built-in schematic editor (control-M) and add a diagram to your question. | |
Aug 5, 2015 at 15:06 | comment | added | Vrisk | @Lorenzo Donati better picture added. | |
Aug 5, 2015 at 14:41 | comment | added | Spehro 'speff' Pefhany | If you overheat the semiconductor too much then the electrons fall into the holes and can't get out. | |
Aug 5, 2015 at 14:14 | comment | added | LorenzoDonati4Ukraine-OnStrike | "As you can see" No, we can't see. You didn't post a schematic and the photo is poor: it is impossible to see the connections of the parts on your breadboard, nor how they are powered (only the red wire from the positive terminal of the battery is shown, where does the negative go?) | |
Aug 5, 2015 at 14:07 | history | asked | Vrisk | CC BY-SA 3.0 |