Timeline for Calculating voltage in a simple circuit
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 12, 2015 at 18:47 | vote | accept | RJSmith92 | ||
| Aug 11, 2015 at 23:44 | comment | added | Peter Bennett | @EMFields: no, you'd have a 109 foot rope - you need a little overlap for the splice... :-) | |
| Aug 11, 2015 at 23:42 | comment | added | EM Fields | @RJSmith92: If you have two ropes, one ten feet long and another 100 feet long, and you splice then together, it doesn't matter which ends get spliced; when you finish you'll have a 110 foot long rope. | |
| Aug 11, 2015 at 23:40 | comment | added | RJSmith92 | Thanks @PeterBennett and Stefan for clearing that up, much appreciated. | |
| Aug 11, 2015 at 23:37 | comment | added | Peter Bennett | Yes, you have to consider all the voltage sources and drops in the whole circuit when determining the current. In a simple series circuit, the order of the components has no effect on the current. | |
| Aug 11, 2015 at 23:33 | comment | added | RJSmith92 | @PeterBennett Thanks Peter, yes I realise now that the current would be reduced. I understand that the current is equal throughout the circuit, but I was thinking if you placed the resistor 'before' the LED, it would 'use up' the 12V before it reached the LED, because 600 Ohm x 0.02mA = 12V, but this excludes the 2V from the LED in the circuit, therefore the current has to drop to 16.7mA, is this correct? | |
| Aug 11, 2015 at 23:14 | comment | added | Peter Bennett | If you used a 600 ohm resistor in place of the 500 ohm, you would still have the 2 volt drop across the LED, so would still have 10 volts across the resistor. Prof. Ohm says that the current would then be 16.7 mA. The order of components in the circuit has no effect on the current. | |
| Aug 11, 2015 at 22:25 | comment | added | RJSmith92 | Thanks @Stefan much appreciated. You've helped clear up my confusion, especially with 'V=IR only works for resistive loads'. Last questions, if we did use a 600 Ohms resistor into the circuit, what would happen? would the LED still work? Would the voltage drop across the resistor be 12V and then be nothing left for the LED, would it matter if the resistor is before or after the LED? Thanks again. | |
| Aug 11, 2015 at 22:08 | history | answered | stefandz | CC BY-SA 3.0 |