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Sep 1, 2015 at 18:47 comment added LvW In this simple case (grounded R in parallel to C) you simply must determine the input impedance of the circuit. That means: The procedure as described in my detailed answer is not necessary.
Sep 1, 2015 at 16:15 comment added Barbaris Andy aka, I'm just using a college book solving problems. It has a simple parallel circuit (cap and resistor) and I just need to build a graph that shows how the impedance (with the phase) changes in a frequency range from 0 to 20kHz
Sep 1, 2015 at 12:47 comment added Andy aka @FakeMoustache I am aware of what you say but I'm challenging the OP to think about what he really wants. Just call it my little suspicion he may want something else than what the question implies (6th sense).
Sep 1, 2015 at 12:38 comment added Bimpelrekkie @Andyaka That is usually true but if that "gain" just happens to be in A/V (transconductance amplifier) instead of the usual V/V (voltage amplifier) then I could still make a bode plot. Same for V/A (impedance). Only the gain would have a different unit. But it would still be and look like a bode plot.
Sep 1, 2015 at 12:34 answer added LvW timeline score: 1
Sep 1, 2015 at 12:28 answer added Bimpelrekkie timeline score: 4
Sep 1, 2015 at 12:06 comment added Andy aka What is your question? Note also that a bode plot is for the gain and phase of a system.
Sep 1, 2015 at 12:05 review First posts
Sep 1, 2015 at 13:42
Sep 1, 2015 at 12:03 history asked Barbaris CC BY-SA 3.0