Timeline for Confusion about why voltage of a cell decreases as it's used up and how it relates to current
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 17, 2015 at 16:06 | vote | accept | Richard Smith | ||
| Sep 17, 2015 at 2:06 | comment | added | Criticizing Israel not allowed | This graph does not relate to the battery being used up. | |
| Sep 17, 2015 at 0:19 | history | tweeted | twitter.com/#!/StackElectronix/status/644304642894073856 | ||
| Sep 16, 2015 at 20:49 | comment | added | Peter Bennett | If you increase the load on a battery (decrease load resistance, add more light bulbs in parallel...) the current delivered by the battery will increase, causing an increased voltage drop across the battery's internal resistance and reducing the voltage measured between the battery terminals. | |
| Sep 16, 2015 at 20:44 | answer | added | Kvegaoro | timeline score: 1 | |
| Sep 16, 2015 at 20:39 | comment | added | Chu | the battery emf causes the current, not the terminal voltage. If you short-circuit the battery, the emf drives a large current through the internal resistance and the short-circuit, but the terminal voltage is zero. | |
| Sep 16, 2015 at 20:23 | answer | added | Andy aka | timeline score: 3 | |
| Sep 16, 2015 at 20:15 | answer | added | Murali | timeline score: 0 | |
| Sep 16, 2015 at 20:14 | comment | added | Richard Smith | I was always taught that it's the VOLTAGE that CAUSES current to flow, not the other way around. So why current increases in the first place? | |
| Sep 16, 2015 at 20:07 | review | First posts | |||
| Sep 16, 2015 at 20:56 | |||||
| Sep 16, 2015 at 20:06 | comment | added | Peter Bennett | You have exchanged cause and effect. The voltage decreases because of the increasing current through the internal resistance. | |
| Sep 16, 2015 at 20:01 | history | asked | Richard Smith | CC BY-SA 3.0 |