Timeline for Design a circuit that would turn off output between two input voltage levels
Current License: CC BY-SA 3.0
20 events
| when toggle format | what | by | license | comment | |
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| Jul 14, 2021 at 12:33 | vote | accept | Viki | ||
| Sep 23, 2015 at 23:34 | comment | added | Olin Lathrop | @EMFi: Actually the slope is 1/2, not 2, for Vin > 5. | |
| Sep 22, 2015 at 16:50 | comment | added | EM Fields | Hmmm... I seem to have glossed over something, which is that when Vin is slewing positive, Vout will have a slope of 1 until Vin gets to -3 volts, when Vout's slope goes to zero. It then stays at zero until Vin gets to 5 volts, then changes to 2 as Vin goes more and more positive. Is that right? If so I'll have to edit my answer since Vout shows a slope of zero for any value of Vin between zero volts and 5 volts, and a slope of 1 everywhere else. | |
| Sep 21, 2015 at 15:49 | comment | added | The Photon | @destrom8, however no window comparator is needed to solve the problem. | |
| Sep 21, 2015 at 15:40 | comment | added | DerStrom8 | @Viki You can use op-amps as comparators. You can create a window comparator using two of them. | |
| Sep 20, 2015 at 17:47 | answer | added | EM Fields | timeline score: 1 | |
| Sep 20, 2015 at 16:44 | comment | added | Viki | ^Exactly! We are meant to use only op-amps, diodes and resistors | |
| Sep 20, 2015 at 16:38 | answer | added | The Photon | timeline score: 3 | |
| Sep 20, 2015 at 16:16 | comment | added | The Photon | Major hint: a window comparator has nothing to do with the solution your instructor expects. | |
| Sep 20, 2015 at 15:50 | comment | added | Viki | @derstrom8 I'll ofcourse do. There's ABSOLUTELY NOTHING to worry about it! | |
| Sep 20, 2015 at 14:42 | answer | added | Olin Lathrop | timeline score: 4 | |
| Sep 20, 2015 at 14:20 | comment | added | DerStrom8 | @Viki we have already given you hints. Look up window comparators. DO SOME WORK ON YOUR OWN! | |
| Sep 20, 2015 at 14:16 | comment | added | EM Fields | What's the range of the input voltage? That is, how far negative and how far positive does it go? | |
| Sep 20, 2015 at 13:56 | comment | added | Viki | This is a last year exam paper, and we are solving for tomorrow's test. You could at-least give few hints for the portion between -3V to +5V | |
| Sep 20, 2015 at 13:40 | comment | added | DerStrom8 | This looks like homework. We are not here to do your homework for you. That's your job. | |
| Sep 20, 2015 at 13:39 | comment | added | Viki | Thanks for the suggestion. Can you make out the circuit for the given transfer characteristics? | |
| Sep 20, 2015 at 13:31 | comment | added | DerStrom8 | I agree, use a window comparator | |
| Sep 20, 2015 at 12:37 | comment | added | Golaž | This can be done with the so called window detector: en.wikipedia.org/wiki/Window_detector | |
| Sep 20, 2015 at 12:29 | review | First posts | |||
| Sep 20, 2015 at 13:06 | |||||
| Sep 20, 2015 at 12:26 | history | asked | Viki | CC BY-SA 3.0 |