Timeline for Solving for an unknown current: Mesh Method, or Node Voltage?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 25, 2015 at 23:11 | comment | added | Dwayne Reid | I'm a tiny bit confused. What other information were you given? Were you actually told what the power dissipated in each resistor was? If so, why isn't that information part of your question? | |
| Sep 25, 2015 at 22:42 | answer | added | The Photon | timeline score: 1 | |
| Sep 25, 2015 at 21:29 | history | edited | LetThisNightExplode | CC BY-SA 3.0 |
added 505 characters in body
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| Sep 25, 2015 at 20:24 | comment | added | Andy aka | Now what is that really complicated theory.... oh yeah ohms law. You can even solve it by not knowing the powers dissipated by each resistor. | |
| Sep 25, 2015 at 19:52 | comment | added | Rahul Behl | Yeah! Power and resistance for each resistor is enough. I hope you know that here: P = I^2 R = (V^2)/R = V*I | |
| Sep 25, 2015 at 19:46 | comment | added | Pete Becker | If you know the power and resistance for each resistor then you know the voltage across and the current through each resistor. That's plenty of information. | |
| Sep 25, 2015 at 19:32 | history | asked | LetThisNightExplode | CC BY-SA 3.0 |