Timeline for How to get output voltage of microphone?
Current License: CC BY-SA 3.0
9 events
when toggle format | what | by | license | comment | |
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Feb 4, 2016 at 19:02 | comment | added | Andy aka | Did you resolve all your issues on this @user3892683 | |
Nov 3, 2015 at 13:45 | comment | added | Andy aka | The mike spec is -41 dBV for a SPL of 94 dB. If output volts drop by 4.3 dB to -45.3 dBV then this is because the SPL has dropped by 4.3 dB to 89.7 dB SPL. | |
Nov 3, 2015 at 13:31 | comment | added | user90392 | And when the dBV is -45.3 then the decibels are 94-(45.3-41) =90 decibels correct? | |
Nov 2, 2015 at 8:20 | comment | added | Andy aka | 5.4mV is -45.3 dBV. Think about it... 1V = 0 dBV, 0.1V is -20 dBV and 0.01V (10mV) is -40 dBV. 5.4mV in dB form is 20*log(5.4E-3). | |
Nov 2, 2015 at 7:30 | comment | added | user90392 | When assuming that it is linear | |
Nov 2, 2015 at 6:30 | comment | added | user90392 | Ok, and if I want to know the decibels for 5.4 mV -> 20log(0.0054/0.0089)=-4.3 dB , correct? | |
Nov 1, 2015 at 21:52 | comment | added | Andy aka | -41 divided by 20 = -2.05. Then take the antilog = 8.9mV. The ratio of voltages in dB terms is 20log10(V1/V2) so I just did the reverse. 0 dBV = 1V RMS. | |
Nov 1, 2015 at 21:29 | comment | added | user90392 | How do you get from -41 dB to 8.9mV? | |
Nov 1, 2015 at 20:32 | history | answered | Andy aka | CC BY-SA 3.0 |