Timeline for Analyzing BJT differential pair with feedback
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 27, 2015 at 18:27 | comment | added | LvW | The gain A is simply the forward gain without any feedback. | |
| Dec 27, 2015 at 16:47 | comment | added | C K | I simply ask where the A circuit is according to this picture: images.slideplayer.com/16/4939071/slides/slide_2.jpg | |
| Dec 27, 2015 at 16:31 | comment | added | Olin Lathrop | @Cetin: I can't make sense of what you are asking. | |
| Dec 27, 2015 at 16:15 | vote | accept | C K | ||
| Dec 27, 2015 at 16:15 | comment | added | C K | Thank you for the answer :) I am trying to draw the whole thing as the series shunt topology, but I can't draw the feedforward circuit... The output of feedback circuit should be in series with the signal, but I can't figure out how. Can you help with that? | |
| Dec 27, 2015 at 14:02 | history | edited | Olin Lathrop | CC BY-SA 3.0 |
added 1 character in body
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| Dec 27, 2015 at 13:57 | history | answered | Olin Lathrop | CC BY-SA 3.0 |
