Timeline for Help me understand capacitor discharging
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| Jan 2, 2016 at 3:24 | comment | added | João Pedro | I read a suggestion that could be good to specify before doing the problem the higher potential of the resistor and the lower. In our case, the higher potential is the left (right?). So then, when analizing the discharging of the capacitor I should get (going clockwise in the loop rule): $-i_dR$. Since $i_d=-i_c$ the term goes positive. Is that right? It may seem i'm over complicating but I think the problem is that I've learned to apply kvl only when current don't change direction, so I calculate as either a drop or a increase in potential according to the direction of current... Thanks. | |
| Jan 2, 2016 at 3:03 | history | answered | The Photon | CC BY-SA 3.0 |