Timeline for Confusion with current in voltage-out amplifier
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Jan 22, 2016 at 14:15 | comment | added | LvW | user16307: OK, I see your point. But a general answer is not possible, because we have to define: What is the "stage" we are referring to? The BJT is regarded as a current source - however, the collector resistor produces a corresponding voltage output. Now, it is up to you to decide if you allocate this resistor to the stage or not. In some other cases the output current is used directly as a base current for another tzransistor (Example: Darlington transistor). In this case, I think it is appropriate to say: I out for the 1st transistor and I in for the second. | |
| Jan 22, 2016 at 13:42 | comment | added | user16307 | in general when you look at a transistor amplifier in a circuit as a stage. what is the criteria you notice and say: aha this is a x in y out amplifier. because current and voltage is always in and out. that was my confusion. | |
| Jan 22, 2016 at 13:34 | comment | added | LvW | @user16307, it is not clear to me what your problem resp. the main question is: The behaviour of (a) the transistor as a stand-alone unit, or (b) a certain circuit with resistors, capacitors and transistors or (c) any other circuit or part? | |
| Jan 22, 2016 at 12:22 | comment | added | user16307 | yes great answer indeed but if you read my question im writing about CE single transistor amplifier before the edit. thanks | |
| Jan 22, 2016 at 12:20 | comment | added | Olin Lathrop | @user: You asked about current-in voltage-out amplifiers. I used a opamp circuit to illustrate the concept and show that these things are actually possible to useful approximations. | |
| Jan 22, 2016 at 12:16 | comment | added | user16307 | im not asking about opamps. please see my edit | |
| Jan 22, 2016 at 12:10 | comment | added | rdtsc | This is a great example of a TIA, but the o.p. doesn't understand the difference between "current-mode" and "voltage-mode" operation. | |
| Jan 22, 2016 at 12:06 | history | answered | Olin Lathrop | CC BY-SA 3.0 |