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Corrected variable mistake
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As you have done begin by calculating the equivalent capacitance of C1, C2, C4, and C5.

Ceq = 40nF

You know that the total voltage across C3 and Ceq must be 48V. This is because C3 and Ceq will have the same charging profile, and thusly the same amount of charge on both capacitors.

Qeq = Q3

and given that:

Q = Vcap * C

C3 * V3 = Ceq * Veq

V3 = 1.67 * Veq

Remembering:

48 + Veq + V3 = 0

we get:

48 + Veq + 1.67 Veq = 0

thus VeqV3 = 30.1V and V3Veq = 17.9V.

From here, rinse and repeat for the remaining capacitors.

As you have done begin by calculating the equivalent capacitance of C1, C2, C4, and C5.

Ceq = 40nF

You know that the total voltage across C3 and Ceq must be 48V. This is because C3 and Ceq will have the same charging profile, and thusly the same amount of charge on both capacitors.

Qeq = Q3

and given that:

Q = Vcap * C

C3 * V3 = Ceq * Veq

V3 = 1.67 * Veq

Remembering:

48 + Veq + V3 = 0

we get:

48 + Veq + 1.67 Veq = 0

thus Veq = 30.1V and V3 = 17.9V.

From here, rinse and repeat for the remaining capacitors.

As you have done begin by calculating the equivalent capacitance of C1, C2, C4, and C5.

Ceq = 40nF

You know that the total voltage across C3 and Ceq must be 48V. This is because C3 and Ceq will have the same charging profile, and thusly the same amount of charge on both capacitors.

Qeq = Q3

and given that:

Q = Vcap * C

C3 * V3 = Ceq * Veq

V3 = 1.67 * Veq

Remembering:

48 + Veq + V3 = 0

we get:

48 + Veq + 1.67 Veq = 0

thus V3 = 30.1V and Veq = 17.9V.

From here, rinse and repeat for the remaining capacitors.

Fixed calculation error
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As you have done begin by calculating the equivalent capacitance of C1, C2, C4, and C5.

Ceq = 40nF

You know that the total voltage across C3 and Ceq must be 48V. This is because C3 and Ceq will have the same charging profile, and thusly the same amount of charge on both capacitors.

Qeq = Q3

and given that:

Q = Vcap * C

C3 * V3 = 0Ceq * Veq

V3 = 1.667 * Veq

Remembering:

48 + Veq + V3 = 0

we get:

48 + Veq + 01.667 Veq = 0

thus Veq = 30V30.1V and V3 = 18V17.9V.

From here, rinse and repeat for the remaining capacitors.

As you have done begin by calculating the equivalent capacitance of C1, C2, C4, and C5.

Ceq = 40nF

You know that the total voltage across C3 and Ceq must be 48V. This is because C3 and Ceq will have the same charging profile, and thusly the same amount of charge on both capacitors.

Qeq = Q3

and given that:

Q = Vcap * C

V3 = 0.6 * Veq

Remembering:

48 + Veq + V3 = 0

we get:

48 + Veq + 0.6 Veq = 0

thus Veq = 30V and V3 = 18V.

From here, rinse and repeat for the remaining capacitors.

As you have done begin by calculating the equivalent capacitance of C1, C2, C4, and C5.

Ceq = 40nF

You know that the total voltage across C3 and Ceq must be 48V. This is because C3 and Ceq will have the same charging profile, and thusly the same amount of charge on both capacitors.

Qeq = Q3

and given that:

Q = Vcap * C

C3 * V3 = Ceq * Veq

V3 = 1.67 * Veq

Remembering:

48 + Veq + V3 = 0

we get:

48 + Veq + 1.67 Veq = 0

thus Veq = 30.1V and V3 = 17.9V.

From here, rinse and repeat for the remaining capacitors.

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As you have done begin by calculating the equivalent capacitance of C1, C2, C4, and C5.

Ceq = 40nF

You know that the total voltage across C3 and Ceq must be 48V. This is because C3 and Ceq will have the same charging profile, and thusly the same amount of charge on both capacitors.

Qeq = Q3

and given that:

Q = Vcap * C

V3 = 0.6 * Veq

Remembering:

48 + Veq + V3 = 0

we get:

48 + Veq + 0.6 Veq = 0

thus Veq = 30V and V3 = 18V.

From here, rinse and repeat for the remaining capacitors.