Figure 5 of the linked datasheet shows there is a small amount of emission in the 380nm+>380 nm range.
I digitized the spectrum and computed how much relative radiant flux there is greater than 380nm380 nm.
\begin{gather} \Phi_{visible} = \frac{\int_{380 nm}^{\infty} \Phi_{\lambda} d \lambda}{\int_{0}^{\infty} \Phi_{\lambda} d \lambda} \approx 0.087 \end{gather}\begin{gather} \Phi_\text{visible} = \frac{\int_\text{380 nm}^{\infty} \Phi_{\lambda} \text{d} \lambda}{\int_{0}^{\infty} \Phi_{\lambda} \text{d} \lambda} \approx 0.087 \end{gather}
So a bit under 10%
10 % of the radiant flux is being emitted in the visible spectrum. I don't know what color this would look like in practice, though I suspect it might be have blue-violet hue since about 88%
88 % of this is in the 380-400nm
380–400 nm range. Assuming 1050mW
1050 mW total radiant flux, this means there's about 92mW
92 mW emitted in the visible spectrum.
You can find "reasonably priced" (~30 USD) shortpass and bandpass filters which transmit UV while blocking visible wavelengths, for example this one. This would reduce the visible radiant flux to about 10-30mW
10–30 mW (eyeball estimated). If you have more money available, there are of course better filters.