Timeline for Low pass filter cutoff frequency calculation [duplicate]
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Feb 24, 2016 at 12:21 | history | closed |
nidhin PeterJ David Daniel Grillo Olin Lathrop |
Duplicate of How do I calculate the cutoff frequency of a low pass rc circuit?, What is the practical reason for associating cut-off frequency to %50 power attenuation? | |
| Feb 24, 2016 at 8:30 | comment | added | LvW | HARI, don`t forget it is a DEFINITION only. And as such it is NOT applied for any kind of filter. It is common to use the 3dB criterion for first-order filters and higher-order filters with BUTTERWORTH response. However, for CHEBYSHEV and CAUER type filter functions we have a different definition (for practical reasons). | |
| Feb 24, 2016 at 6:13 | answer | added | seshu | timeline score: -1 | |
| Feb 24, 2016 at 5:28 | comment | added | user57037 | The cutoff frequency is chosen to be the half-power point mostly by convention. It is convenient, and easy to calculate for RC filters. If you would like to know why the half-power point corresponds to 1/sqrt(2), well, it just does. From an intuitive perspective, it is because power is V^2/R. If you say V1^2 / R = 2(V2^2)/R, and then solve for V1/V2, you will get the sqrt(2) ratio. | |
| Feb 24, 2016 at 5:11 | review | Close votes | |||
| Feb 24, 2016 at 12:21 | |||||
| Feb 24, 2016 at 4:55 | history | edited | uint128_t | CC BY-SA 3.0 |
Added MathJax, fixed grammar
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| Feb 24, 2016 at 3:47 | history | asked | HARI | CC BY-SA 3.0 |