Timeline for 8 bit addressable latch at 3.3V with open drain output
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Feb 28, 2016 at 12:13 | comment | added | Fabio | Thanks for your comments. Actually I need to drive each led individually because they are in different locations. I need 10-30 mA but, since I'm usign the raspberry, I have few mA at 3.3V and a lot of power at 5V: I could use some 3.3 logic without open-drain but in this case I should use a dc-dc from 5 to 3.3V to provide the needed power. | |
| Feb 27, 2016 at 19:16 | answer | added | Filipe Nicoli | timeline score: 1 | |
| Feb 27, 2016 at 17:13 | comment | added | WhatRoughBeast | How much current per LED do you need? | |
| Feb 27, 2016 at 17:12 | comment | added | WhatRoughBeast | @WoutervanOoijen - but not the TPIC6B259. | |
| Feb 27, 2016 at 16:13 | comment | added | Wouter van Ooijen | Do you really need 40 individual outputs? Above a few LEDs a matrix is ofte used. More complex is software, but less hardware. For the 3.3 -> 5V issue: check the datsheets, most 5V logic chips will accept a 3.3V input, especially HCT chips. | |
| Feb 27, 2016 at 15:48 | review | First posts | |||
| Feb 27, 2016 at 16:39 | |||||
| Feb 27, 2016 at 15:44 | history | asked | Fabio | CC BY-SA 3.0 |