Timeline for Function of characteristic curve of DC motors
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Mar 9, 2016 at 15:51 | comment | added | mghis | Yes, it is quite weird, but there isn't any variable coupling. Gear ratio is 21/65 and wheels have a diameter 1210 mm. But I have noticed that in the graph from the first link you posted the torque/current relation is also linear and not quadratic. I do not understand why. | |
| Mar 9, 2016 at 8:02 | comment | added | Marko Buršič | @mghis The weird part is that torque is linear, but it shall be quadratic, perhaps some variable coupling in between motor and the wheel? | |
| Mar 8, 2016 at 22:00 | comment | added | mghis | I had indeed tried the equation I = (V)/(R+KS) (where I = current, V = tension, R = resistance, S = speed) but could not solve it to get results consistent with the graphic. Indeed the function is similar to the graphic but I cannot find values for R and K giving approximately the same results of the graph. | |
| Mar 8, 2016 at 21:20 | comment | added | Marko Buršič | You find it in every book of electric motors. vlab.ee.nus.edu.sg/~bmchen/courses/EG1108_DCmotors.pdf equation 17, 19 | |
| Mar 8, 2016 at 21:13 | comment | added | mghis | From a mathematical point of view, the graphic is y = f(x), where y is speed and x is current. I need the function "f". | |
| Mar 8, 2016 at 21:07 | comment | added | mghis | I tried to explain what the graph represents in the original question. I know that the six motors are series wound (I wrote that above). I need an equation which relates speed and voltage to current according to the graphic. | |
| Mar 8, 2016 at 18:51 | history | answered | Marko Buršič | CC BY-SA 3.0 |