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Edit: Re-interpreting the value shown on the datasheet. The resistance shown is not M\$\Omega\$, much lower, more like 3400 ohms based on the change in the switching times with external gate resistor.

This does in fact really slow the switching when the gate charge is high, such as the 1.6ms minimum off switching time with a 15V 1.5A load. The asymmetric switching time implies they may actually have a diode across the resistor to speed the 'on' time. The diode will be reverse-biased when clamping, as explained below.

A large value resistor will not likely protect the gate anyway, it's a permanent breakdown and insulation damage that occurs, not like a diode breakdown. That's why the ESD zener diodes are on the gate lead, to prevent excessive gate-source voltage.

So, why put any resistor at all in there you ask? Well it's so the other (Overvoltage) zeners can do their thing. Imagine the worst case and we short the gate lead to the source, and then sadistically increase the voltage on the drain (through some external load) waiting for the D-S breakdown. When the current through the zener diodes exceeds some mA the MOSFET turns on and clamps the overvoltage.

Power MOSFETs are generally not very sensitive to ESD anyway, because of the large gate capacitance. The gate actually breaks down at something like 50V or more typically so a lot of energy has to reach the gate. Tiny MOSFETs such as RF MOSFETs are very sensitive to ESD in comparison.

Edit: Re-interpreting the value shown on the datasheet. The resistance shown is not M\$\Omega\$, much lower, more like 3400 ohms based on the change in the switching times with external gate resistor.

This does in fact really slow the switching when the gate charge is high, such as the 1.6ms minimum off switching time with a 15V 1.5A load. The asymmetric switching time implies they may actually have a diode across the resistor to speed the 'on' time. The diode will be reverse-biased when clamping, as explained below.

A large value resistor will not likely protect the gate anyway, it's a permanent breakdown and insulation damage that occurs, not like a diode breakdown. That's why the ESD zener diodes are on the gate lead, to prevent excessive gate-source voltage.

So, why put any resistor at all in there you ask? Well it's so the other (Overvoltage) zeners can do their thing. Imagine the worst case and we short the gate lead to the source, and then sadistically increase the voltage on the drain (through some external load) waiting for the D-S breakdown. When the current through the zener diodes exceeds some mA the MOSFET turns on and clamps the overvoltage.

Power MOSFETs are generally not very sensitive to ESD anyway, because of the large gate capacitance. The gate actually breaks down at something like 50V-100V typically so a lot of energy has to reach the gate. Tiny MOSFETs such as RF MOSFETs are very sensitive to ESD in comparison. However, the typical human body model of ESD is enough to damage even a moderately large power MOSFET gate.

The resistance shown is not M\$\Omega\$, try 9\$\Omega\$ At least that is the lowest value shown on the datasheet.

Anything much more than 5-10\$\Omega\$ would slow the switching excessively for many applications (and they are wanting to sell that to everyone possible). M\$\Omega\$ would slow the switching to many milliseconds not hundreds of ns.

A large value resistor will not likely protect the gate anyway, it's a permanent breakdown and insulation damage that occurs, not like a diode breakdown. That's why the ESD zener diodes are on the gate lead, to prevent excessive gate-source voltage.

So, why put any resistor at all in there you ask? Well it's so the other (Overvoltage) zeners can do their thing. Imagine the worst case and we short the gate lead to the source, and then sadistically increase the voltage on the drain (through some external load) waiting for the D-S breakdown. When the current through the zener diodes exceeds a couple A the MOSFET turns on and clamps the overvoltage. If the current is less than that, the zener + 9 ohms clamps it through the gate (possibly affecting whatever is connected to the gate! ).

Edit: Re-interpreting the value shown on the datasheet. The resistance shown is not M\$\Omega\$, much lower, more like 3400 ohms based on the change in the switching times with external gate resistor.

This does in fact really slow the switching when the gate charge is high, such as the 1.6ms minimum off switching time with a 15V 1.5A load. The asymmetric switching time implies they may actually have a diode across the resistor to speed the 'on' time. The diode will be reverse-biased when clamping, as explained below.

A large value resistor will not likely protect the gate anyway, it's a permanent breakdown and insulation damage that occurs, not like a diode breakdown. That's why the ESD zener diodes are on the gate lead, to prevent excessive gate-source voltage.

So, why put any resistor at all in there you ask? Well it's so the other (Overvoltage) zeners can do their thing. Imagine the worst case and we short the gate lead to the source, and then sadistically increase the voltage on the drain (through some external load) waiting for the D-S breakdown. When the current through the zener diodes exceeds some mA the MOSFET turns on and clamps the overvoltage.

Power MOSFETs are generally not very sensitive to ESD anyway, because of the large gate capacitance. The gate actually breaks down at something like 50V or more typically so a lot of energy has to reach the gate. Tiny MOSFETs such as RF MOSFETs are very sensitive to ESD in comparison.

The resistance shown is not M\$\Omega\$, try 9\$\Omega\$ (read the datasheet).

Anything much more than 5-10\$\Omega\$ would slow the switching excessively for many applications (and they are wanting to sell that to everyone possible). M\$\Omega\$ would slow the switching to many milliseconds not hundreds of ns.

A large value resistor will not likely protect the gate anyway, it's a permanent breakdown and insulation damage that occurs, not like a diode breakdown. That's why the ESD zener diodes are on the gate lead, to prevent excessive gate-source voltage.

So, why put any resistor at all in there you ask? Well it's so the other (Overvoltage) zeners can do their thing. Imagine the worst case and we short the gate lead to the source, and then sadistically increase the voltage on the drain (through some external load) waiting for the D-S breakdown. When the current through the zener diodes exceeds a couple A the MOSFET turns on and clamps the overvoltage. If the current is less than that, the zener + 9 ohms clamps it through the gate (possibly affecting whatever is connected to the gate! ).

The resistance shown is not M\$\Omega\$, try 9\$\Omega\$ At least that is the lowest value shown on the datasheet.

Anything much more than 5-10\$\Omega\$ would slow the switching excessively for many applications (and they are wanting to sell that to everyone possible). M\$\Omega\$ would slow the switching to many milliseconds not hundreds of ns.

A large value resistor will not likely protect the gate anyway, it's a permanent breakdown and insulation damage that occurs, not like a diode breakdown. That's why the ESD zener diodes are on the gate lead, to prevent excessive gate-source voltage.

So, why put any resistor at all in there you ask? Well it's so the other (Overvoltage) zeners can do their thing. Imagine the worst case and we short the gate lead to the source, and then sadistically increase the voltage on the drain (through some external load) waiting for the D-S breakdown. When the current through the zener diodes exceeds a couple A the MOSFET turns on and clamps the overvoltage. If the current is less than that, the zener + 9 ohms clamps it through the gate (possibly affecting whatever is connected to the gate! ).