Timeline for How to charge a battery + check voltage?
Current License: CC BY-SA 3.0
10 events
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Dec 20, 2011 at 9:51 | comment | added | AndrejaKo | @Gulbahar As I said, on the lighter the ring is - and the tip is +, so that's what you need to connect to the battery.You now have two options: to buy a cigarette lighter socket and connect it to battery and plug the unmodified adapter to it or to connect wires directly to the adapter as I described. | |
Dec 20, 2011 at 9:29 | comment | added | Gulbahar | Thanks Andreja. The cigarette lighter-to-USB charger that comes with the GPS says that it expects 12/24V/1A as input, and offers 5V/1.2A as output. How could I connect the big lead battery to that cigarette lighter? | |
Dec 19, 2011 at 0:14 | history | edited | AndrejaKo | CC BY-SA 3.0 |
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Dec 19, 2011 at 0:07 | comment | added | AndrejaKo | @Gulbahar I updated my answer. | |
Dec 19, 2011 at 0:07 | history | edited | AndrejaKo | CC BY-SA 3.0 |
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Dec 18, 2011 at 23:45 | comment | added | AndrejaKo | @Gulbahar I wanted to continue my explanation here but I'll post it in my answer instead because it's too long. | |
Dec 18, 2011 at 23:39 | comment | added | AndrejaKo | @Gulbahar In theory yes, but the solution will not be very elegant. The main problem with the modification is that lead-acid batteries store considerable amount of energy and the chargers need considerable power to charge the batteries efficiently. Most cheap and simple ways of getting 6 V (or 5 V if you want to charge battery that level) work for relatively small currents. For example if you use a linear regulator like say 7805, to charge the battery at 1 A, you'd get (12 V - 5 V)* 1 A= 6 W of heat which needs to be dissipated on the regulator and that's quite a lot. | |
Dec 18, 2011 at 20:23 | comment | added | Gulbahar | Thanks for the great explanation. Can 12V chargers be configured to provide 6V voltage instead? | |
Dec 16, 2011 at 19:45 | history | edited | AndrejaKo | CC BY-SA 3.0 |
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Dec 16, 2011 at 19:35 | history | answered | AndrejaKo | CC BY-SA 3.0 |