Timeline for Why stepping up voltage during transmission considers \$I^2 R\$ but not \$\frac{V^2}{R}\$?
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| S Dec 6, 2023 at 14:21 | history | suggested | Pedro Reis | CC BY-SA 4.0 |
fix formula presentationv + added schematic for visual people like me
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| Dec 6, 2023 at 12:30 | review | Suggested edits | |||
| S Dec 6, 2023 at 14:21 | |||||
| Jun 9, 2016 at 0:45 | comment | added | Peter Green | Well you can look at it either way. Increasing the voltage reduces the loss for a given size of cable or reduces the size of cable needed for a given loss. | |
| Jun 9, 2016 at 0:19 | comment | added | user16307 | I was thinking the motivation is to reduce the cross section of transmission lines hence the costs. One might need a very thick line to pass the current if voltage were not stepped up. | |
| Jun 9, 2016 at 0:14 | history | answered | Peter Green | CC BY-SA 3.0 |