Timeline for Equivalent "capacitative reactance" for calculating rms current under mixed-frequency AC voltage waveform
Current License: CC BY-SA 3.0
6 events
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| Jun 30, 2016 at 12:57 | comment | added | user115412 | Thanks again! So if I know my rms Voltage, can I calculate an equivalent capacitance as alluded to in my previous comment (note, I've created a new question just about this issue:electronics.stackexchange.com/questions/243674/…) | |
| Jun 30, 2016 at 12:52 | comment | added | Captainj2001 | @Bey You can calculate Thevenin equivalent circuits in the frequency domain using the same method, i.e., finding the short circuit current and open circuit voltage between two nodes. Your Thevenin equivalent circuit will just have a complex impedance instead of a real resistance. | |
| Jun 30, 2016 at 12:42 | comment | added | user115412 | Specifically, I was hoping that I could calculate my "equivalent reactance" \$X_c(f)\$ and get the rms current as \$I_{rms}=\frac{V_{rms}}{X_c(f)}\$ | |
| Jun 30, 2016 at 12:37 | vote | accept | CommunityBot | ||
| Jun 30, 2016 at 12:37 | comment | added | user115412 | Thank you! I was trying to find out the distribution of the current if the voltage source were white noise (gaussian). So it looks there is no simple "thevenin-equivalent" circuit operating at fixed frequency (which is what I was hypothesizing in my post). | |
| Jun 30, 2016 at 12:27 | history | answered | Captainj2001 | CC BY-SA 3.0 |