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In the above sum there is no need to conisiderconsider the red one as the four 1's are already mapped by blue and green group.So So the answer will be:

                     F= CD'E'+A'BC'E+A'BDE'
   ' REPRESENTS -

$$F = C{\overline D}{\overline E}+{\overline A}B{\overline C}E+{\overline A}BD{\overline E}$$

In the above sum there is no need to conisider the red one as the four 1's are already mapped by blue and green group.So the answer will be

                     F= CD'E'+A'BC'E+A'BDE'
   ' REPRESENTS -

In the above sum there is no need to consider the red one as the four 1's are already mapped by blue and green group. So the answer will be:

$$F = C{\overline D}{\overline E}+{\overline A}B{\overline C}E+{\overline A}BD{\overline E}$$

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In the above sum there is no need to conisider the red one as the four 1's are already mapped by blue and green group.So the answer will be

                     F= CD'E'+A'BC'E+A'BDE'
   ' REPRESENTS -