Timeline for How one can increase voltage given by a battery?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Sep 21, 2016 at 7:36 | comment | added | Andy aka | Quiescent current will be about 300 uA - if this is too much then look for a different regulator. | |
| Sep 21, 2016 at 4:17 | comment | added | Tristanto | I think it will work well on low current, probably will produce ripple voltage but it will not effect to the calculator. | |
| Sep 21, 2016 at 3:59 | history | edited | pipe | CC BY-SA 3.0 |
Hid the horrible url
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| Sep 21, 2016 at 3:59 | comment | added | DIYser | Is there a version of this circuit that provides an output of 14V @ 2A? If not, what would a person need to do to make such a circuit? | |
| Sep 21, 2016 at 3:46 | comment | added | Miguel Henrique Salviatti | oh nice, and it works well on low currents? Because the calculator needs some 50uA when in standby so it can retain it's memory | |
| Sep 21, 2016 at 3:37 | history | edited | Tristanto | CC BY-SA 3.0 |
added 481 characters in body
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| Sep 21, 2016 at 3:29 | history | answered | Tristanto | CC BY-SA 3.0 |