Timeline for Why phase bump causes signal distortion in source follower?
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 25, 2017 at 12:16 | vote | accept | emnha | ||
| Oct 20, 2016 at 3:53 | comment | added | emnha | Yes, with phase bump, we also can restore it by passing the output through a matching inverse filter with a phase bump too? | |
| Oct 20, 2016 at 3:49 | comment | added | Dave Tweed | Yes, the bump causes any frequency components of an input signal that fall within its range to be delayed relative to other frequency components. This causes the waveform to change in appearance -- but the original appearance can be restored by passing the output through a matching inverse filter. THAT is why the term "distortion" is not normally used in this situation. | |
| Oct 20, 2016 at 3:45 | comment | added | emnha | "Yes, the bump in the phase response will cause the output waveform to be different from the input waveform." Could you explain this sentence? Why bump cause the difference? Is it the phase difference? | |
| Oct 20, 2016 at 3:37 | comment | added | Dave Tweed | Well, as I tried to explain in my answer, that is NOT my definition of distortion. | |
| Oct 20, 2016 at 3:00 | comment | added | emnha | With distortion, I think we have the same definition - output waveform is different from input waveform. However, it may be too general. I this case I mean the output waveform is of the same phase with input waveform. The magnitude is assumed to be the same. So if pole and zero are far from each other, the output and input waveforms are also different in phase. Not Not sure if that is also what you meant by distortion. | |
| Oct 19, 2016 at 18:27 | comment | added | Dave Tweed | It seems that we are talking past each other without reaching a mutual understanding. Perhaps you should more precisely define what you meant by "distortion" in your original question. | |
| Oct 19, 2016 at 18:11 | comment | added | emnha | Sorry I still don't understand what you mean by this "the bump in the phase response will cause the output waveform to be different from the input waveform". Output and input waveforms are always different at frequencies around pole and zero regardless they are close or not. | |
| Oct 19, 2016 at 11:28 | comment | added | Dave Tweed | No, I'm talking about the phase "bump" and the fact that amplitudes to the right of the bump are lower than to the left. How far apart the pole and zero are merely affects the magnitude of these two effects. | |
| Oct 19, 2016 at 5:29 | comment | added | emnha | Thank you. With "distortion" I thought that it is phase shift that can not be compensated for. I saw it somewhere but I can't find it now. With "both of these effects" do you mean that one with phase bump and the one when pole and zero are far from each other? | |
| Oct 18, 2016 at 16:55 | history | answered | Dave Tweed | CC BY-SA 3.0 |