Timeline for BC337 transistor appears to be in active mode, but has too small Vbe
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Dec 23, 2016 at 17:20 | comment | added | D.A.S. | Yes it has a narrow hFE gain window for linearity. There are many other ways to do it as well. You ought to be able to get >4Vpp keeping away from Vce(sat) and Vce(max (Imin>10%) | |
| Dec 23, 2016 at 15:55 | comment | added | Mahkoe | @TonyStewart.EEsince'75 Haha thanks for asking. However, I figured that one out on my own. I reduced the gain of the amplifier (by putting the bypass capacitor on the slider of a potentiometer), and that almost completely removed any distortion. | |
| Dec 22, 2016 at 0:42 | comment | added | D.A.S. | @Mahkoe Do you want an undistorted sine out? you never asked. | |
| Dec 20, 2016 at 9:17 | history | tweeted | twitter.com/StackElectronix/status/811138466830548992 | ||
| Dec 20, 2016 at 4:29 | comment | added | Mahkoe | OK, guess I didn't know how to interpret that. In that case everything is fine. Thanks! | |
| Dec 20, 2016 at 4:28 | vote | accept | Mahkoe | ||
| Dec 20, 2016 at 4:25 | answer | added | The Photon | timeline score: 6 | |
| Dec 20, 2016 at 4:20 | comment | added | Rohat Kılıç | The value shown as 1.2VDC in the datasheet is the "maximum" value of Vbe. As you might know, typical silicon transistors have about 0.6-0.7VDC, so your Vbe measurement is correct. But for Ie, if you measure 7mA then the voltage across R6 should be 7V, but the supply voltage is 5V. How can it be? If you make DC analysis then you can easily see that quiescent collector (or emitter) current is about (1.25-0.6)/1k=0.65mA. But since this is an oscillator, you might not able to measure DC currents. | |
| Dec 20, 2016 at 4:09 | history | asked | Mahkoe | CC BY-SA 3.0 |