Timeline for How do I use this voltage regulator with a digital pinout?
Current License: CC BY-SA 3.0
10 events
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| Mar 18, 2012 at 11:25 | comment | added | shimofuri | @RussellMcMahon As the flag koan goes (ralphmag.org/AR/why.html), it is the mind that programs the regulator. ;-) Whether it is current or voltage, Thevenin or Norton, it's all relative. The more convenient wins. | |
| Mar 18, 2012 at 11:12 | comment | added | Russell McMahon♦ | NO! - Vout is set to Vadj + 1.2V. This DOES cause varous currents to flow, and you do need a specified minimum Iout BUT the device is fundamentally voltage controlled by the voltage at pin Vadj. | |
| Mar 18, 2012 at 10:39 | vote | accept | Matt | ||
| Aug 1, 2012 at 19:28 | |||||
| Mar 18, 2012 at 10:11 | comment | added | Matt | So do I need resistors? | |
| Mar 18, 2012 at 10:06 | comment | added | shimofuri | @Matt Regarding your diagram, you need to follow exactly the template of how the regulator is used. | |
| Mar 18, 2012 at 10:02 | comment | added | shimofuri | In its typical application, it is programmed by current Iadj. Please see "Application Hints" on page 9. Why current? Because these regulators operate on "floating mode". In fact, you can use it for regulating at higher voltages: national.com/ms/LB/LB-47.pdf | |
| Mar 18, 2012 at 9:55 | comment | added | Matt | @PetPaulsen that's the assumption that I made when I ordered these, and thought that the resistors were just a convenience for more common circuits. It doesn't seem to work that way though - is my diagram correct? | |
| Mar 18, 2012 at 9:46 | comment | added | PetPaulsen | IMO, the voltage is not regulated by the current on the ADJ pin, but by the voltage applied to the ADJ pin. A comperator in the voltage regulator compares the voltage applied to the ADJ pin with the internal voltage reference. | |
| Mar 18, 2012 at 9:39 | history | edited | shimofuri | CC BY-SA 3.0 |
added 118 characters in body
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| Mar 18, 2012 at 9:34 | history | answered | shimofuri | CC BY-SA 3.0 |