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Jul 25, 2019 at 2:38 vote accept jotadepicas
Feb 19, 2017 at 21:27 answer added Guill timeline score: 1
Feb 15, 2017 at 14:27 comment added Bort @jotadepicas - The power consumption of a buffer should be very very small, but it could have an impact. I imagine that it would work by using a Schmidt trigger or similar hysteresis effect, which would pull 4.9V levels back up to 5V (for example).
Feb 15, 2017 at 14:25 comment added Bimpelrekkie do you know what this chipset might actually be doing It would be similar to a USB hub with only one port. You could use a USB hub and only connect one port and leave the others open.
Feb 15, 2017 at 14:22 comment added jotadepicas @Bort so I assume this strategy would not work for devices that might need all available current, only for low-consuming devices with a power source of their own (a printer, for example).
Feb 15, 2017 at 14:21 comment added jotadepicas @PeterSmith I see, you say the chipset may be drawing some current but not enough to affect the current being provided to actually power the connected device? Also, do you know what this chipset might actually be doing? Just re-transmitting at a higher power or something like that?
Feb 15, 2017 at 14:20 comment added Bort It could sacrifice power for data. Thus you'd lose some current but gain signal amplification.
Feb 15, 2017 at 14:19 comment added PlasmaHH I have a black box that contains a DC/DC to boost the incoming voltage up to 5.25V and then uses that on the line to the attached USB device. Works fine.
Feb 15, 2017 at 14:17 comment added Peter Smith USB cables carry power and I expect that is being used; a very low power chipset would probably not affect the power delivery to the downstream device very much.
Feb 15, 2017 at 14:12 history asked jotadepicas CC BY-SA 3.0