Timeline for Energy in capacitors - loss?
Current License: CC BY-SA 3.0
11 events
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May 11, 2012 at 14:49 | history | edited | stevenvh | CC BY-SA 3.0 |
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Apr 9, 2012 at 15:00 | vote | accept | Federico Russo | ||
Apr 9, 2012 at 14:47 | comment | added | stevenvh | @Federico - Right, but Olin describes a hypothetical system of perfect, lossless components. The same kind of hypothetical components allows you to create a perpetuum mobile as well, which in practice is as impossible as Olin's perpetuum oscillator. | |
Apr 9, 2012 at 14:44 | comment | added | Federico Russo | Apparently Olin can move energy in and out without penalty.. | |
Apr 9, 2012 at 14:00 | comment | added | stevenvh | @Federico - Yes, the first. You have to perform work (energy) to move energy in or out a closed system (the capacitor). | |
Apr 9, 2012 at 13:51 | comment | added | Federico Russo | "you can't do that unpunished". Why not? Laws of thermodynamics? | |
Apr 9, 2012 at 13:07 | comment | added | clabacchio | I know, it wasn't meant to be a rigorous demonstration, just to show that the less energy is justified by the fact that "entropy", or disorder, is increased and that decreases the energy. | |
Apr 9, 2012 at 12:31 | comment | added | stevenvh | @clabacchio - your "less potential energy" doesn't show the energy loss, just like the energy loss isn't obvious from the lower voltage without the formula. | |
Apr 9, 2012 at 11:56 | comment | added | clabacchio | I'll add that since the equalizing process is spontaneous, it must happen at the expense of energy. As in the water analogy, if you split the water between two containers placed at the same height, the average height of it will be lower, which means less potential energy (mgh). | |
Apr 9, 2012 at 9:11 | history | edited | stevenvh | CC BY-SA 3.0 |
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Apr 9, 2012 at 9:01 | history | answered | stevenvh | CC BY-SA 3.0 |