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Timeline for Energy in capacitors - loss?

Current License: CC BY-SA 3.0

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May 11, 2012 at 14:49 history edited stevenvh CC BY-SA 3.0
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Apr 9, 2012 at 15:00 vote accept Federico Russo
Apr 9, 2012 at 14:47 comment added stevenvh @Federico - Right, but Olin describes a hypothetical system of perfect, lossless components. The same kind of hypothetical components allows you to create a perpetuum mobile as well, which in practice is as impossible as Olin's perpetuum oscillator.
Apr 9, 2012 at 14:44 comment added Federico Russo Apparently Olin can move energy in and out without penalty..
Apr 9, 2012 at 14:00 comment added stevenvh @Federico - Yes, the first. You have to perform work (energy) to move energy in or out a closed system (the capacitor).
Apr 9, 2012 at 13:51 comment added Federico Russo "you can't do that unpunished". Why not? Laws of thermodynamics?
Apr 9, 2012 at 13:07 comment added clabacchio I know, it wasn't meant to be a rigorous demonstration, just to show that the less energy is justified by the fact that "entropy", or disorder, is increased and that decreases the energy.
Apr 9, 2012 at 12:31 comment added stevenvh @clabacchio - your "less potential energy" doesn't show the energy loss, just like the energy loss isn't obvious from the lower voltage without the formula.
Apr 9, 2012 at 11:56 comment added clabacchio I'll add that since the equalizing process is spontaneous, it must happen at the expense of energy. As in the water analogy, if you split the water between two containers placed at the same height, the average height of it will be lower, which means less potential energy (mgh).
Apr 9, 2012 at 9:11 history edited stevenvh CC BY-SA 3.0
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Apr 9, 2012 at 9:01 history answered stevenvh CC BY-SA 3.0