Timeline for Confusion on the purpose of using active current-meters
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 15, 2017 at 17:35 | vote | accept | user1245 | ||
| Apr 15, 2017 at 17:26 | comment | added | user1245 | With the circuit diagram and a few notes below it makes a lot difference in understanding. Thanks | |
| Apr 15, 2017 at 17:11 | history | edited | The Photon | CC BY-SA 3.0 |
added 519 characters in body
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| Apr 15, 2017 at 17:06 | comment | added | user1245 | As far as I understand there are two issues here. One of them is if one measures the output voltage, the measuring device's input resistance will have affect on the measurement. This depends on how big the Rmeter(in second figure) as well. The second issue is the "current source seeing some load impedance" before the input to the opamp. I think I understand the first one, but the second one is a bit confusing since the load resistance will be in series with the current source and why would it have affect on the current. A simple illustration would help a lot if you have time, thanks | |
| Apr 15, 2017 at 17:00 | comment | added | The Photon | Because real current sources have nonzero output conductance. | |
| Apr 15, 2017 at 16:57 | comment | added | user1245 | You wrote "In the second circuit, the source sees a load impedance equal to the resistor value, which could change the current it produces." Why would the current change? | |
| Apr 15, 2017 at 16:40 | history | answered | The Photon | CC BY-SA 3.0 |