Timeline for Common emitter with low voltage input
Current License: CC BY-SA 3.0
13 events
when toggle format | what | by | license | comment | |
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May 6, 2017 at 21:45 | answer | added | dannyf | timeline score: 0 | |
May 6, 2017 at 21:42 | answer | added | jonk | timeline score: 1 | |
May 6, 2017 at 20:22 | comment | added | Hearth | @OskarSkog I meant R5, in fact. R4 is on the upper end of reasonable, if you make R2 larger. R5 is much too big to be an effective output filter; it would take quite some time from turn-on to stabilize. | |
May 6, 2017 at 19:41 | comment | added | jonk | You get to use a zero impedance driver, as shown? And that nearly infinite output impedance? Cool. You might want to examine my relatively full answer here (having something like this available is why I sometimes write more): electronics.stackexchange.com/questions/291774/… It's not an AC grounded emitter design like yours. But that's because your arrangement may need global negative feedback to linearize, stabilize against temps, etc. | |
May 6, 2017 at 17:58 | comment | added | Oskar Skog | @Felthry: Don't you mean R4? | |
May 6, 2017 at 16:54 | answer | added | Spehro 'speff' Pefhany | timeline score: 1 | |
May 6, 2017 at 16:50 | comment | added | Finbarr | Oh, and ask your lecturer or tutor how much it should be amplified by otherwise it's hard to work out the values you need. | |
May 6, 2017 at 16:46 | comment | added | Finbarr | Learn how to design it, there are plenty of resources online. Like this one | |
May 6, 2017 at 16:42 | comment | added | Dan | @Finbarr so what would be a good way to fix it? | |
May 6, 2017 at 16:20 | comment | added | Finbarr | As it stands, the base of Q1 is biased at 0.5V so it's probably not turning on at all. | |
May 6, 2017 at 16:19 | comment | added | Hearth | Most noticeably, your R2 is far too small and R5 is far too large. | |
May 6, 2017 at 16:14 | review | First posts | |||
May 6, 2017 at 16:52 | |||||
May 6, 2017 at 16:13 | history | asked | Dan | CC BY-SA 3.0 |