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May 11, 2017 at 2:27 comment added gyroninja Looks like with them shorted it would immediately disconnect. Leaving pin 4 floating seems to make it work correctly, though my pcb is kind of a mess now.
May 8, 2017 at 6:12 comment added Tom L. You should not short them. Pin 4 should be floating for your application. A PC will not take care of that since the USB-A <-> Micro-USB-A cable probably just has 4 pins but once you connect your device to another micro-usb port it won't probably work as the ID pin decides between host and peripheral mode.
May 7, 2017 at 11:30 vote accept gyroninja
May 7, 2017 at 11:30 comment added gyroninja Thanks man. I just shorted pin 4 and 5 and it worked. :)
May 7, 2017 at 11:05 comment added Tom L. In addition, it appears that all your pins are backward (at least if the unconnected pin is pin 5). Double check with the datasheet (right side of the datasheet shows the footprint from Top and labels Pins1 and 5)
May 7, 2017 at 11:00 comment added Tom L. Your VCCIO doesn't match the CPLD OR the FT245RL, something is wrong with your voltage generation. VCREF appears to be wrong as well. I'm wondering: Either you're measuring wrong or you shouldn't have been able to program the CPLD
May 7, 2017 at 10:56 comment added Tom L. Micro USB-B is NOT USB-B .. your connector in the schematic has 4 pins, wheras micro-usb-b has 5. In your connector, Pin 4 is ground - for Micro-USB-B GND would be 5.
May 7, 2017 at 10:40 comment added gyroninja * I'm using this micro usb port. Here's pic related showing the usb port. * The traces are ~1.5mm. *No clue what that is, so no. *PCB stackup is 2 layers (copper) *Yes, I programmed my cpld earlier. *VCC: 1.379 VCCIO: 1.227 *What do you mean, there would be no power *There is no short
May 7, 2017 at 5:21 history answered Tom L. CC BY-SA 3.0