Timeline for Is it a disadvantage for a generator to supply both resistive and reactive current to its load?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Nov 4, 2020 at 15:38 | comment | added | alejnavab | @Taven Reactive current corresponds to reactive power, which is related to a lossless transfer of energy between the source and the load. However, it indeed causes losses in the wires, because they have resistance, and whenever current passes (be it active current or reactive current) it will cause heat as per Joule's law. | |
| May 18, 2017 at 14:23 | comment | added | StainlessSteelRat | There are inductive and resistive losses to transmission lines, motor windings, transformer windings, etc. The power you get out is less than the power in. Hence losses. | |
| May 18, 2017 at 13:41 | comment | added | Taven | @StainlessSteelRat Even though the reactive power does not contribute to the real power losses, in this case, the reactive currents and impedances contribute to losses? How is that possible? | |
| May 18, 2017 at 13:29 | comment | added | StainlessSteelRat | @Taven The losses are more \$ I_{Total}^2\times R\$ and \$ I_{Total}^2\times X\$. But overall, Yes. | |
| May 18, 2017 at 12:17 | comment | added | Taven | So in the second case there would be both (I_resistive^2)* R losses and (I_reactive)^2*R losses? | |
| May 18, 2017 at 11:47 | history | answered | Olin Lathrop | CC BY-SA 3.0 |