Timeline for What are the best methods to efficiently reduce the power in a 120v circuit?
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
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| May 22, 2017 at 19:15 | comment | added | sstobbe | @Jiojyojoe a standard light dimmer will drive a restive load, but having 100+ degC heater wire at mains voltages needs a lot of care to be safe. | |
| May 22, 2017 at 19:09 | comment | added | Jiojyojoe | @sstobbe I like that thought. But in this application I would like to run several units off a multiple pole relay, for a total of up to 2000 watts. | |
| May 22, 2017 at 4:58 | comment | added | Oskar Skog | Half-wave rectification will cause a horrible power factor. I'd suggest a transformer (~ 1:0.7) instead, and perhaps/if needed a largish capacitor (if in doubt, use X-rated) to counteract the inductive load of the transformer. | |
| May 22, 2017 at 2:15 | comment | added | D.A.S. | Start with your acceptable measurable specs, Pd, ΔTmax , ΔV , Rmax, minimum efficiency ε and medium (air , oil, water, metal tank etc) !!! These are all critical to answer. | |
| May 22, 2017 at 1:33 | answer | added | MadHatter | timeline score: 1 | |
| May 21, 2017 at 23:49 | comment | added | Asmyldof | Do also note that the same resistance at double the voltage will dissipate four times the power. I = V / R; P = V * I = V * V/R; <-- V counts twice, so doubling it will quadruple P. | |
| May 21, 2017 at 23:30 | comment | added | Ian Bland | For the diode, simply work out the current and multiply by the forward voltage at that current. If it's rectifying AC, so only doing a 50% duty cycle, divide by 2. You'll need to get the forward voltage at the particular current from the graph on its datasheet. | |
| May 21, 2017 at 22:26 | comment | added | sstobbe | Do you need 120v can you design around an old atx computer power supply? | |
| May 21, 2017 at 22:11 | review | First posts | |||
| May 21, 2017 at 22:54 | |||||
| May 21, 2017 at 22:01 | history | asked | Jiojyojoe | CC BY-SA 3.0 |