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Jun 4, 2017 at 0:55 history edited Veda Sadhak CC BY-SA 3.0
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Jun 4, 2017 at 0:46 comment added Veda Sadhak I am using the CSD19533KCS which is a 100V 86A mosfet. Also I have posted a picture with the scope measurements with reference to ground it still shows the slow fall time in the high-side gate drives.
Jun 4, 2017 at 0:42 history edited Veda Sadhak CC BY-SA 3.0
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Jun 3, 2017 at 10:06 answer added Andy aka timeline score: 3
Jun 3, 2017 at 3:51 comment added W5VO With 100Ω gate resistors, you're not going to see that fast of a gate transition, but I suspect that isn't the reason you're having issues. You haven't mentioned which power MOSFET you're using. That oscilloscope can't do two isolated differential measurements without additional equipment - this is a common beginner's mistake which is why exact connection points for each probe are necessary for further information.
Jun 3, 2017 at 3:41 history edited W5VO CC BY-SA 3.0
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Jun 3, 2017 at 3:37 comment added Sredni Vashtar So, to be clear: are you using differential probes? Otherwise, the ground clip of both probes is attached where?
Jun 3, 2017 at 3:05 comment added Veda Sadhak @brhans ... You are right, my bad guys I saw the push-pull on that block diagram and assumed it was BJTs, it is actually using MOSFETs. I apologize for that mistake OlinLathrop. Note: I had to remove that block diagram because I can only upload 2 pictures.
Jun 3, 2017 at 3:02 history edited Veda Sadhak CC BY-SA 3.0
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Jun 3, 2017 at 2:57 history edited Veda Sadhak CC BY-SA 3.0
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Jun 3, 2017 at 2:12 comment added brhans There are no BJTs in that block diagram...
Jun 3, 2017 at 1:19 comment added Veda Sadhak Will upload circuit soon.
Jun 3, 2017 at 1:18 comment added Veda Sadhak @OlinLathrop W5VO is right the BJT push-pull configuration I am talking about are shown in the block diagram.
Jun 3, 2017 at 1:17 comment added Veda Sadhak @sstobbe The probes are connected between the gate and source of both MOSFETs directly. You are right it is swinging below -5vdc and I am not exactly sure how that is happenin, but my guess is that it has something to do with the charge pump of the driver IC.
Jun 3, 2017 at 0:50 comment added Sredni Vashtar Where are the BJTs? And how did you connect your probes to the circuit?
Jun 2, 2017 at 23:26 comment added W5VO @OlinLathrop I think you're confusing the block diagram of the driver IC he's using with his circuit schematic (which is not included/shown).
Jun 2, 2017 at 23:01 comment added WhatRoughBeast As Andy aka says, show your circuit. Most particularly show your load. If the DRV_HI output is floating, then a high output will drive quickly to Vcc, but a low output will simply discharge the output capacitance very slowly.
Jun 2, 2017 at 22:49 answer added D.A.S. timeline score: -2
Jun 2, 2017 at 22:30 review Close votes
Jun 4, 2017 at 6:01
Jun 2, 2017 at 21:46 comment added Andy aka Show your exact circuit.
Jun 2, 2017 at 21:35 comment added sstobbe How are you probing both outputs? The blue trace looks like it's swinging to -5vdc when the high side driver switches
Jun 2, 2017 at 21:24 history asked Veda Sadhak CC BY-SA 3.0