Timeline for What happens when one of the 3 Phase load is disconnected suddenly?
Current License: CC BY-SA 3.0
15 events
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| Jun 25, 2017 at 20:07 | comment | added | Andy aka | You could also make a spreadsheet calculator for this. I see there is one on-line. I had a quick look for an unbalanced load calculator but there isn't one. I think your current is about right in the first one. I'm sorry I can't calculate with accuracy. | |
| Jun 25, 2017 at 19:09 | comment | added | Andy aka | I'm sorry, Im not going to be able to find the time tonight to look in detail but a cursory glance tells me you have the right approach. You can double check the numbers by using a sim tool of course. | |
| Jun 25, 2017 at 18:02 | comment | added | Prietess | Hi Andy, hopefully you don't forget, hehe. Thanks a lot for your kind help! | |
| Jun 24, 2017 at 17:28 | comment | added | Prietess | Added answer to part (b) as well above. Is this also what you mean for part (b)? as simple as that? Because I thought it won't be that straight forward. Hope to hear from you when you have time to look at it, Thank you! | |
| Jun 24, 2017 at 16:29 | comment | added | Prietess | Added answer to part (a) above at my question, is that what you mean? as simple as that? Because I thought it won't be that straight forward. Thank you! | |
| Jun 24, 2017 at 16:19 | comment | added | Prietess | Okay, I can just write first and I will attach it above (by editting my question above), you can take a look when you have time. | |
| Jun 24, 2017 at 16:16 | comment | added | Andy aka | Not tonight dude. I'm going to be busy. | |
| Jun 24, 2017 at 16:14 | comment | added | Prietess | I will write down my solutions, may I ask your kind help to check whether that is what you mean? give me half an hour (max) please. | |
| Jun 24, 2017 at 16:13 | comment | added | Andy aka | Now I'm confused as to what you ask. | |
| Jun 24, 2017 at 16:10 | comment | added | Prietess | Sorry Andy, because I was reading this source here and I expected that my phase current (which is same with line current for star) will increase when one of the line is disconnected. marineinsight.com/marine-electrical/… It would be good if you could give a simple enlightenment to me on why they are different....? | |
| Jun 24, 2017 at 16:07 | comment | added | Prietess | Wait, Andy, for part(a), when phase Y is normal, not disconnected, my phase voltage VRN is 240V (angle 0) (if I set it as reference), VYN is 240V (Angle -120), and VBN is 240V(Angle 120). Now, when Y is disconnected, are you saying that they all do not change? If yes, hence no change in phase current also, and hence IN=IR+IB, just 1 term less than the case when Y is not disconnected. But it seems a bit unrealistic to me,.... (I might think too much). Sorry, I am unexperienced on this. Thanks again! | |
| Jun 24, 2017 at 16:04 | comment | added | Andy aka | Correct but it's different for part b of course. | |
| Jun 24, 2017 at 16:02 | comment | added | Prietess | Hellooooooo! Thanks for your answers and explanation. for (a), which is star connection, Yes, I know how to calculate the neutral line current for unbalanced load, which is just IR+IY+IB. If I just set Z2 to infinity, that means simply IY=0, and if the sqrt(3) is still true, that means there is no change to my phase voltage of star-connection, still 240V (415/sqrt(3)), and hence no increase in my phase currents of phase R and B even though Y is disconnected? Because it seems not so logical to me. | |
| Jun 24, 2017 at 10:45 | history | edited | Andy aka | CC BY-SA 3.0 |
added 443 characters in body
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| Jun 24, 2017 at 10:38 | history | answered | Andy aka | CC BY-SA 3.0 |