Timeline for Voltage and current gain of a voltage divider bias amplifier
Current License: CC BY-SA 3.0
20 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 9, 2018 at 14:47 | answer | added | LvW | timeline score: 2 | |
| Apr 9, 2018 at 12:46 | answer | added | Barry | timeline score: 0 | |
| Apr 9, 2018 at 12:28 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Mar 6, 2018 at 5:02 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Feb 3, 2018 at 3:20 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jan 1, 2018 at 6:58 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Dec 2, 2017 at 1:32 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Oct 26, 2017 at 20:08 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Sep 26, 2017 at 3:43 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jul 20, 2017 at 19:29 | comment | added | Andy aka | Strictly speaking, when the input voltage increases, the output voltage decreases i.e. this type of amplifier is an inverting type. In a good amplifier and ignoring inversion, the gain should remain close to constant. | |
| Jul 20, 2017 at 19:20 | comment | added | Alex | @Andyaka whenever the input voltage increases the out put voltage also increases and vice versa. so in this case the gain (change in output/change in input) will not remain constant ? may be they do not remain constant because a a small change in input voltage cause a very big change in output voltage so the gain increases ?please say your opinion | |
| Jul 20, 2017 at 19:07 | comment | added | Andy aka | Correct, correct. | |
| Jul 20, 2017 at 18:09 | comment | added | Alex | @Andyaka actually the gain is the ratio of change in output voltage to change in input voltage . if we have emitter resistor then the input voltage will be Vb (from base to ground). if there is no emitter resistor then we the input voltage will be from base to emitter because now emitter is at ground and base to ground or base to emitter are now same things. same would be the case with output voltage which in from collector to ground. right ? | |
| Jul 19, 2017 at 18:59 | comment | added | Alex | so if the by pass capacitor isnt there then how the voltage gain will be defined? | |
| Jul 18, 2017 at 11:36 | comment | added | Andy aka | If the bypass capacitor is low impedance at the frequencies you are considering then yes, you can. If the bypass capacitor isn't there then no, you can't. | |
| Jul 18, 2017 at 11:03 | comment | added | Alex | @Andyaka can we say that voltage gain is : peak to peak ac Vce/peak to peak ac Vbe in this case? | |
| Jul 17, 2017 at 14:30 | answer | added | analogsystemsrf | timeline score: 0 | |
| Jul 17, 2017 at 7:17 | comment | added | Andy aka | Voltage gain is not Vce/Vbe - it's Vc/Vb both relative to 0 volts. | |
| Jul 17, 2017 at 6:55 | comment | added | jonk | You've been asking about this relatively simple BJT amplifier configuration more than once. It's clear you don't understand much, yet. See my discussion here: electronics.stackexchange.com/questions/303778/… . It may help some. But I don't think anyone here is prepared to walk you from how far back you are now to where you need to be. It's daunting to consider it. You need to get back to simpler questions, I think. | |
| Jul 17, 2017 at 6:42 | history | asked | Alex | CC BY-SA 3.0 |