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Dec 5, 2017 at 14:09 comment added 12431234123412341234123 Edit: Sorry had a error: it is 2^7 - 7 - 8 + 2^10 = 1137 Devices / Channel => 1137 * 65536 = 74514432 Devices. But there may be more possible when you use IO-Expander to turn on and off some Buffers (What is far form practical use but a theoretical possibility).
Dec 5, 2017 at 13:57 comment added 12431234123412341234123 No, you will still be limited: 4 Channels/ Multiplexer, per channel you have 4 Subchannels, then you have subsubchannels, subsubsubchannels and more. You have 3 Address-lines per channelswitcher: Is 4^(2^3)=65536 channels. Per channel you have 2^8 - 7 - 8 + 2^10 = 1265 Devices / Channels (When you also use Buffers) (the -7 are for reserved addresses and -8 for the multiplex addresses). 1265 *65536 = 82903040 Maximum Devices.
Aug 7, 2017 at 10:12 history answered filo CC BY-SA 3.0