Timeline for Voltage for motor driver
Current License: CC BY-SA 3.0
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| Aug 10, 2017 at 13:29 | comment | added | math3006 | You can provide a bit more than 3V without burning your motor. 3.6V Ni-Mh should be okay. There are some diodes on the path, so the voltage will drop down a bit. 2.4V is okay if you don't need much torque though. In general, never use a resistor to lower a power supply voltage. Use diodes for quick and cheap applications, or voltage regulators. | |
| Aug 9, 2017 at 23:03 | vote | accept | Noctiphobia | ||
| Aug 9, 2017 at 22:11 | comment | added | Noctiphobia | Thanks, I think I understand it now. So, I should provide exactly 3V to the driver, and 7-12V to the arduino, right? And if I want to power everything with 1.2V Ni-MH batteries, should I get 3x1.2V for the motors and 6x1.2V for the Arduino, and add resistors to the motors to bring it to 3V, or 2x1.2V (since the operating range is 1.5-3V)? | |
| Aug 9, 2017 at 22:00 | comment | added | math3006 | You can link the power inputs, but your Arduino won't start with 3V, and your motors will burn with 9V. Motor sypply voltage is not suitable to power an Arduino. Moreover, it's good practive to separate power supply to avoid µC reset in case of voltage dropout due to motor overconsumption. | |
| Aug 9, 2017 at 21:57 | comment | added | Noctiphobia | But the pololu page says this: "Shield can optionally power the Arduino base directly when motor supply voltage is suitable" - and the "suitable" part is what I don't understand. | |
| Aug 9, 2017 at 21:53 | comment | added | math3006 | You still need to provide 2 different voltages to the module. On the schematic : pololu.com/file/0J803/… you can see that you have Vin (3V, for the motors) and Ard_Vin (9V, for the Arduino). The module simply link the 5V from the arduino with the logical side of the driver. | |
| Aug 9, 2017 at 21:48 | comment | added | Noctiphobia | The datasheet you linked is a datasheet of a TI DRV8835 - The Pololu DRV8835 I'm using is based on it, but provides additional functions. I can plug in external power, and when I put a jumper on the VOUT pins, it can provide power to Arduino. | |
| Aug 9, 2017 at 21:47 | review | First posts | |||
| Aug 10, 2017 at 1:04 | |||||
| Aug 9, 2017 at 21:44 | history | answered | math3006 | CC BY-SA 3.0 |