Timeline for Convolution with two unbounded signals
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 3, 2017 at 15:38 | vote | accept | Adam | ||
| Oct 3, 2017 at 1:28 | answer | added | The Photon | timeline score: 1 | |
| Oct 3, 2017 at 1:18 | comment | added | Adam | Ah I was looking for \$\infty\$ but I was more worried about getting my point across. As for not having a \$\tau\$, that was just me mistranscribing my notes. So what I see here is that I need to use t to 0, instead of \$-\infty\$ to 0. | |
| Oct 3, 2017 at 0:43 | comment | added | The Photon |
Also, \$\infty\$ in Mathjax is \infty.
|
|
| Oct 3, 2017 at 0:42 | comment | added | The Photon | It eleminates the problem because with the \$u(t)\$ term (flipped and shifted) you don't end up integrating out to infinity but only out to \$\tau=t\$. (Some of your equations are integrating with respect to \$\tau\$ but don't have a \$\tau\$ in the expression being integrated...I think you've missed some cases where \$t\$ gets changed to \$\tau\$.) | |
| Oct 3, 2017 at 0:33 | comment | added | Adam | Ah, that's probably the issue with my solution. The one thing I would ask is how that might eliminate the issue? I would assume it does that because \$\int u(t)\$ is \$\delta(t)\$? | |
| Oct 3, 2017 at 0:11 | comment | added | The Photon | Are you sure the function in your first graph is supposed to be \$e^{-t}\$ and not \$e^{-t}u(t)\$? Because the second of those is much more commonly encountered in signal processing and Laplace transform problems, and it eliminates the issue you're asking about. Also your graph as drawn appears to show \$e^{-t}u(t)\$. | |
| Oct 2, 2017 at 23:47 | history | edited | Adam | CC BY-SA 3.0 |
Added solution using Laplace
|
| Oct 2, 2017 at 23:26 | history | edited | Adam | CC BY-SA 3.0 |
added 672 characters in body
|
| Oct 2, 2017 at 23:08 | review | First posts | |||
| Oct 3, 2017 at 2:57 | |||||
| Oct 2, 2017 at 23:06 | history | asked | Adam | CC BY-SA 3.0 |