Timeline for Why does armature current increase when load on the DC motor increase?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 8, 2017 at 16:17 | vote | accept | Vishwa Mithra Tatta | ||
| Oct 8, 2017 at 15:13 | answer | added | Transistor | timeline score: 2 | |
| Oct 8, 2017 at 11:12 | comment | added | Russell McMahon♦ | What they said: Motor acts as an alternator and makes voltage to oppose drive voltage. Steady state occurs when Vapplied - Vback_EMF x I motor balances load power. When load is increased motor speed drops so BEMF drops so Vsupply-Vbemf is larger so current and power increase until stability is reached. | |
| Oct 8, 2017 at 10:44 | comment | added | user16324 | If you're wondering where "back EMF" comes from, remember the motor is also a generator. If you turned the shaft by hand (or water or wind power) you'd just call it EMF. Slow down, decrease EMF, it cancels out less of the power source, hence more V across the same armature R. | |
| Oct 8, 2017 at 10:07 | comment | added | Marko Buršič | The speed is decreased, the BEMF voltage is decreased, too. So you have to feed more current: \$V=I\cdot R +V_{BEMF}\$ | |
| Oct 8, 2017 at 10:02 | comment | added | Kevin White | Look up "Back EMF" | |
| Oct 8, 2017 at 9:09 | history | asked | Vishwa Mithra Tatta | CC BY-SA 3.0 |