Timeline for Dual power supply circuit
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Oct 11, 2017 at 20:32 | comment | added | Frosty | The datasheet you linked to says the dropout voltage is ~1-1.2V for the regulator you selected. You might want to consider a different part. | |
| Oct 11, 2017 at 16:19 | comment | added | Vasil Kalchev | This is the diode circuit. My device works on 3.3V regulated. This regulator will work while the battery voltage is above ~3.5V. | |
| Oct 11, 2017 at 15:05 | comment | added | Frosty | What "diode circuit" are you referring to? What is the acceptable Vmin of your device? | |
| Oct 11, 2017 at 14:55 | comment | added | Wesley Lee | Whenever you close SW1, you'll be shorting 5V to BAT+ through the body diode of M2. | |
| Oct 11, 2017 at 14:44 | history | edited | Vasil Kalchev | CC BY-SA 3.0 |
Added a question.
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| Oct 11, 2017 at 14:43 | comment | added | Vasil Kalchev |
The question got lost in the alt tag of the schematic. I'm asking if it will work. 3.3V LDO voltage regulator, P MOSFET, logic level, TP4056 Li-ion charger, the batteries are 18650 Li-ion. I don't want to use the diode circuit because half the battery won't get used.
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| Oct 11, 2017 at 12:45 | comment | added | Transistor | @VasilKalchev: That is very interesting but why are you telling us this? Do you have a question? Do you have datasheet links to the devices mentioned? | |
| Oct 11, 2017 at 12:00 | comment | added | Rohat Kılıç | electronics.stackexchange.com/questions/261179/… | |
| Oct 11, 2017 at 10:34 | history | asked | Vasil Kalchev | CC BY-SA 3.0 |