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Nov 9, 2017 at 13:07 vote accept Jack
Nov 9, 2017 at 1:29 comment added user80875 Ws must be the synchronous speed and Wo the slip speed to satisfy the basic principles of the equivalent circuit.
Nov 8, 2017 at 10:35 history edited user80875 CC BY-SA 3.0
Added "Motor & Load Torque vs Speed" paragraph and diagram
Nov 8, 2017 at 9:47 comment added user80875 To avoid extended discussion in comments, I revised my answer. Comments that have been covered can be deleted.
Nov 8, 2017 at 9:45 history edited user80875 CC BY-SA 3.0
Added 2 paragraphs "To further explain the concept"
Nov 8, 2017 at 4:19 comment added Jack okay, just conceptually. Is it clear from the problem that the load also has output speed? I mean, is it always the case that the torque of load = torque of rotor? If yes, then speed of rotor = speed of load, correct? There's only one speed of stator = which is the speed of the magnetic field induced in stator by alternating currents, in rad/s (also known as synchronous speed)?
Nov 8, 2017 at 1:07 comment added user80875 If the several problems are not from the same source, the notation may be different. I think Wo must be synchronous speed and Ws must be slip speed, but to be sure, I would need to derive it from the form I am more familiar with, speed (n) in RPM and slip (s) as a fraction of synchronous speed. I don't seem to have the patience to sort that out right now.
Nov 7, 2017 at 23:21 comment added Jack To find equivalent impedance, I need to know what's \$R_R \cdot \frac{w_0}{w_s - w_0} \$ is. What's \$w_0\$. Is it the output of whatever was loaded? So it's like output of the load? Is it gonna be equal to rotor speed? Also, if \$w_m = w_r \$ how come they're not the same in this problem: i.imgur.com/b1qrGi1.png
Nov 7, 2017 at 21:32 history edited user80875 CC BY-SA 3.0
Revised answer per comment
Nov 7, 2017 at 21:11 comment added Jack well I still don't know how \$ I_{stator} \$ was found, is it \$V_s\$ divided by equivalent impedance?
Nov 7, 2017 at 14:48 history answered user80875 CC BY-SA 3.0