There are probably a few ways to do this, but I would do it this way.

Calculate \$R_B = R_E * (H_{FE} + 1) = 44 * 101 = 4444\Omega\$

Your circuit then becomes

^{simulate this circuit – Schematic created using CircuitLab}

You should then be able to calculate \$V_B\$.

From superstition theory...

\$V_B = V_{CC} * \frac{R2||R_B}{R1 + R2||R_B} + V_{BE} * \frac{R1||R2}{R_B + R1||R2}\$

Now you know that, you can calculate \$I_B\$

\$I_B = \frac{V_B - V_{BE}}{R_B}\$

\$V_E\$ is simply \$V_B - V_{BE}\$

To check your work calculate \$V_E\$ the other way

\$V_E = I_B * (H_{FE} + 1) * R_E\$

and verify \$I_B + I_{R2} = I_{R1}\$

There are probably a few ways to do this, but I would do it this way.

Calculate \$R_B = R_E * (H_{FE} + 1) = 44 * 101 = 4444\Omega\$

Your circuit then becomes

^{simulate this circuit – Schematic created using CircuitLab}

You should then be able to calculate \$V_B\$.

From superstition theory...

\$V_B = V_{CC} * \frac{R2||R_B}{R1 + R2||R_B} + V_{BE} * \frac{R1||R2}{R_B + R1||R2}\$

where || means in parallel with.

Now you know that, you can calculate \$I_B\$

\$I_B = \frac{V_B - V_{BE}}{R_B}\$

\$V_E\$ is simply \$V_B - V_{BE}\$

To check your work calculate \$V_E\$ the other way

\$V_E = I_B * (H_{FE} + 1) * R_E\$

and verify \$I_B + I_{R2} = I_{R1}\$

There are probably a few ways to do this, but I would do it this way.

Calculate \$R_B = R_E * (H_{FE} + 1) = 44 * 101 = 4444\Omega\$

Your circuit then becomes

^{simulate this circuit – Schematic created using CircuitLab}

You should then be able to calculate \$V_B\$.

From superstition theory...

\$V_B = V_{CC} * \frac{R2||R_B}{R1 + R2||R_B} + V_{BE} * \frac{R1||R2}{R_B + R1||R2}\$

Now you know that, you can calculate \$I_B\$

\$I_B = \frac{V_B - V_{BE}}{R_B}\$

\$V_E\$ is simply \$V_B - V_{BE}\$

To check your work calculate \$V_E\$ the other way

\$V_E = I_B * (H_{FE} + 1) * R_E\$

There are probably a few ways to do this, but I would do it this way.

Calculate \$R_B = R_E * (H_{FE} + 1) = 44 * 101 = 4444\Omega\$

Your circuit then becomes

^{simulate this circuit – Schematic created using CircuitLab}

You should then be able to calculate \$V_B\$.

From superstition theory...

\$V_B = V_{CC} * \frac{R2||R_B}{R1 + R2||R_B} + V_{BE} * \frac{R1||R2}{R_B + R1||R2}\$

Now you know that, you can calculate \$I_B\$

\$I_B = \frac{V_B - V_{BE}}{R_B}\$

\$V_E\$ is simply \$V_B - V_{BE}\$

To check your work calculate \$V_E\$ the other way

\$V_E = I_B * (H_{FE} + 1) * R_E\$

and verify \$I_B + I_{R2} = I_{R1}\$