Timeline for How to determine the saturation level when an opamp schmitt trigger starts worknig?
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Jan 9, 2018 at 16:48 | comment | added | Raafat Abualazm | I have proteus, but in anything Analog it is Garbage really. Gonnna try your suggested software, thanks! | |
| Jan 9, 2018 at 14:06 | comment | added | Andy aka | You can put capacitors in the feedback loop but seriously, if you want to try this either download LTSpice or student edition of micro-cap 11 - the latter is my preferred choice of simulator and you can try these things out and get a better definitive feel for things. | |
| Jan 9, 2018 at 13:42 | comment | added | MCG | Oh.... yeah sorry, I must have read that differently! | |
| Jan 9, 2018 at 13:20 | comment | added | Raafat Abualazm | That I meant. Sorry, I'm having hard times these days. But what happens if I replace a resistor with a capacitor in the postive feedback loop. | |
| Jan 9, 2018 at 13:16 | comment | added | Andy aka | @RaafatAbualazm I'm not sure your original comment made sense - forcing something to be undeterminate doesn't mean anything sensible. Forcing something to be determinate does. As MCG comments, keep it below the thresholds continues keeping it undeterminate but I don't think this is what you are asking about. I think you are asking how to make the output unambiguously high or low at power-up. To do this you can use a capacitor to the negative rail from the non-inverting input to keep the output low or, a cap from pos rail to keep the output high at power-up. | |
| Jan 9, 2018 at 13:01 | comment | added | MCG | If you want to force it to be indetermined, keep it below the thresholds | |
| Jan 9, 2018 at 12:58 | comment | added | Raafat Abualazm | Then how to force it to become undeterminate? | |
| Jan 9, 2018 at 12:28 | history | answered | Andy aka | CC BY-SA 3.0 |