Skip to main content
added 55 characters in body; edited tags
Source Link
W5VO
  • 19.3k
  • 7
  • 64
  • 96

I have a bulb rated 110v110 V, 60 wW and is in series with another bulb which is 110v 110w110 V, 110 W. ItsIt's being powered with a 220 vV source. Now, whtwhat would be the resistance of the resistor to be added in parallel to the first bulb so that each bulb will get the rated power?

The way i will approachI approached this is first get the resistnceresistance of each bulb, then get the voltage drop of each bulb via current divider principle. After that, im stockI'm stuck. Thanks

Ps: its around 302.5 ohmsenter image description here

I have a bulb rated 110v, 60 w and is in series with another bulb which is 110v 110w. Its being powered with a 220 v source. Now, wht would be the resistance of the resistor to be added in parallel to the first bulb so that each bulb will get the rated power?

The way i will approach this is first get the resistnce of each bulb, then get the voltage drop of each bulb via current divider principle. After that, im stock. Thanks

Ps: its around 302.5 ohms

I have a bulb rated 110 V, 60 W and is in series with another bulb which is 110 V, 110 W. It's being powered with a 220 V source. Now, what would be the resistance of the resistor to be added in parallel to the first bulb so that each bulb will get the rated power?

The way I approached this is first get the resistance of each bulb, then get the voltage drop of each bulb via current divider principle. After that, I'm stuck.

enter image description here

Source Link
vvavepacket
  • 2.5k
  • 11
  • 41
  • 57

Calculating parallel resistance of a rated bulb

I have a bulb rated 110v, 60 w and is in series with another bulb which is 110v 110w. Its being powered with a 220 v source. Now, wht would be the resistance of the resistor to be added in parallel to the first bulb so that each bulb will get the rated power?

The way i will approach this is first get the resistnce of each bulb, then get the voltage drop of each bulb via current divider principle. After that, im stock. Thanks

Ps: its around 302.5 ohms