Timeline for Confusion regarding eddy current losses
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 17, 2018 at 16:48 | answer | added | Andy aka | timeline score: 2 | |
| Mar 17, 2018 at 16:40 | answer | added | user103380 | timeline score: 2 | |
| Mar 17, 2018 at 16:26 | answer | added | Tustique | timeline score: 0 | |
| Mar 17, 2018 at 16:26 | comment | added | Deep | @analogsystemsrf but is the current same as in previous case? or is the induced emf same? or is it due to change in impedance of eddy current paths? Sry but can you please explain little bit in detail ^^". | |
| Mar 17, 2018 at 16:02 | comment | added | analogsystemsrf | At higher frequencies, the induced current uses a thinner region of the metal (right at the surface ---- check into Skin Effect) and that region becomes hotter with less power needed. | |
| Mar 17, 2018 at 15:57 | comment | added | Deep | @winny yes but if induced emf is constant, which shall be case if supply voltage is constant, will then the product of Bm and f remain constant? In that case how would eddy losses change? Because they're directly proportional to square of the product? | |
| Mar 17, 2018 at 15:55 | history | edited | Deep | CC BY-SA 3.0 |
added 8 characters in body
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| Mar 17, 2018 at 15:49 | comment | added | winny | Induced EMF =! Eddy current losses. | |
| Mar 17, 2018 at 15:47 | history | edited | Deep | CC BY-SA 3.0 |
edited title
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| Mar 17, 2018 at 15:33 | history | asked | Deep | CC BY-SA 3.0 |