Skip to main content
6 events
when toggle format what by license comment
Jan 13, 2019 at 3:02 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Mar 23, 2018 at 16:25 answer added EE_socal timeline score: 1
Mar 23, 2018 at 6:31 comment added analogsystemsrf One square of copper foil of thickness 1.4 mils (the standard) has 1/2 milliohm resistance. At 30 amps, the power in that square (whatever size square) is IIR or 0.45 watts. In 10cm square, this is OK. In 1cm square, this is already too hot. In via with 1mm depth and 1mm periphery (also a perfect square, so is 0.5 milliohm), you'll have risk of a charred or discolored PCB due to heat. Can you extract 0.45 watts from a tiny plated-thru hole?
Mar 23, 2018 at 0:23 comment added Warren Hill There is a track width calculator here but given your positive load current needs a return path why do you think via stitching will help? If you have positive and ground on both sides of the board it can but I would be considering either thicker copper or supplementing it in some way. Soldering copper braid in parallel may be an option for small quantities or mechanically mounted copper bars for larger ones. A single layer of 70um copper requires about 60mm wide tracks
Mar 23, 2018 at 0:23 comment added D.A.S. You can work out the voltage drop but this method demands a lot of solder fil. A better approach is a thruhole bus bar,
Mar 23, 2018 at 0:07 history asked weirdgyn CC BY-SA 3.0