Timeline for LM2586 - Inductor Heats Then Burns
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 5, 2018 at 17:45 | vote | accept | Rohat Kılıç | ||
| S Mar 30, 2018 at 14:49 | history | suggested | Peter Mortensen | CC BY-SA 3.0 |
Copy edited. Added information from comments (that information belongs here in the answer, not in comments).
|
| Mar 30, 2018 at 13:15 | review | Suggested edits | |||
| S Mar 30, 2018 at 14:49 | |||||
| Mar 29, 2018 at 19:44 | comment | added | AlmostDone | When the switch is off, charge is pumped into C34 and is drained off by the load. With the diode shorted, C34 no longer holds that charge when the switch is on, but quickly decreases toward zero. The feedback senses the drop and the switching controller commands a longer on time to build up a higher current in the inductor. When this on time becomes long enough, the inductor will saturate. When saturated, it no longer functions as an inductor, and the current through L10 will be limited by only its winding resistance and applied voltage. | |
| Mar 29, 2018 at 17:19 | comment | added | Rohat Kılıç | Okay but, dont misunderdtand, I couldnt understand how this results in burning the power inductor. Could you please elaborate? | |
| Mar 29, 2018 at 16:52 | comment | added | Uwe | A 60 V diode for 57 V DC out max? Better use one with 70 V. | |
| Mar 29, 2018 at 16:19 | history | answered | AlmostDone | CC BY-SA 3.0 |