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isam
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maybe the designer of this circuit is relying in the output impedance of the sinusoidal voltage source circuit (there is no ideal voltage source ,every voltage source has an equivalent output impedance) i thinks thats why the input voltage is very low to get a low current suitable for the zeners becouse output impedance is usually low ,for example if the sinusoidal signal comes from a function generator who has an output impedance equals 50 ohms (common) then the current through the zeners will be just .5mA (piece of cake for the zeners)

maybe the designer of this circuit is relying in the output impedance of the sinusoidal voltage source circuit (there is no ideal voltage source ,every voltage source has an equivalent output impedance) for example if the sinusoidal signal comes from a function generator who has an output impedance equals 50 ohms (common) then the current through the zeners will be just .5mA (piece of cake for the zeners)

maybe the designer of this circuit is relying in the output impedance of the sinusoidal voltage source circuit (there is no ideal voltage source ,every voltage source has an equivalent output impedance) i thinks thats why the input voltage is very low to get a low current suitable for the zeners becouse output impedance is usually low ,for example if the sinusoidal signal comes from a function generator who has an output impedance equals 50 ohms (common) then the current through the zeners will be just .5mA (piece of cake for the zeners)

Source Link
isam
  • 101
  • 1
  • 9

maybe the designer of this circuit is relying in the output impedance of the sinusoidal voltage source circuit (there is no ideal voltage source ,every voltage source has an equivalent output impedance) for example if the sinusoidal signal comes from a function generator who has an output impedance equals 50 ohms (common) then the current through the zeners will be just .5mA (piece of cake for the zeners)