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You cannot look at the system thermal dynamics, you must also understand the thermal heat transfer in between system input and output.
The lack of understanding of heat transfer leads to incorrect and inappropriate comments such as this:

30W needs > 30sq in passive surface area or heatsink + cpu fan for both
– Tony Stewart older than dirt

To see how surface area can be used for convective cooling see Section 3.1.1 Example: Calculating the Required Board Size to Hit a Target θJA, in the thermal design reference below.

If you actually needed to dissipate 30W, it is not practical using a rule of thumb that applies to much lower power dissipation. It neglects the other rule of thumb that says 4 oz copper should be used for 6+ watt.

The main purpose of a copper plane is to spread the heat transferring the heat from the junction to ambient as quickly as possible. To use convection heat transfer which is the cross sectional area of the copper thickness and width.

A good source for PCB thermal design is Texas Instruments Application Note 2020 Thermal Design By Insight, Not Hindsight

It is very unlikely that the conductive capability of a PCB's planar copper cross sectional (copper oz) area would be capable of transferring 30 watts of heat flux. Convection is highly dependent on the difference in temperature between ambient and the surface. When the heat is conducted across the copper plane it creates a temperature gradient where the temperature furthest away from the regulator is too inefficient to be effective for convection heat transfer.

Once you have sufficient exposed copper to attach a heatsink, heatsink selection is more empirical experimentation than thermal calculations.

You cannot look at the system thermal dynamics, you must also understand the thermal heat transfer in between system input and output.
The lack of understanding of heat transfer leads to incorrect and inappropriate comments such as this:

30W needs > 30sq in passive surface area or heatsink + cpu fan for both
– Tony Stewart older than dirt

To see how surface area can be used for convective cooling see Section 3.1.1 Example: Calculating the Required Board Size to Hit a Target θJA, in the thermal design reference below.

If you actually needed to dissipate 30W, it is not practical using a rule of thumb that applies to much lower power dissipation. It neglects the other rule of thumb that says 4 oz copper should be used for 6+ watt.

The main purpose of a copper plane is to spread the heat transferring the heat from the junction to ambient as quickly as possible. To use convection heat transfer which is the cross sectional area of the copper thickness and width.

A good source for PCB thermal design is Texas Instruments Application Note 2020 Thermal Design By Insight, Not Hindsight

It is very unlikely that the conductive capability of a PCB's planar copper cross sectional (copper oz) area would be capable of transferring 30 watts of heat flux. Convection is highly dependent on the difference in temperature between ambient and the surface. When the heat is conducted across the copper plane it creates a temperature gradient where the temperature furthest away from the regulator is too inefficient to be effective for convection heat transfer.

Once you have sufficient exposed copper to attach a heatsink, heatsink selection is more empirical experimentation than thermal calculations.

You cannot look at the system thermal dynamics, you must also understand the thermal heat transfer in between system input and output.

The main purpose of a copper plane is to spread the heat transferring the heat from the junction to ambient as quickly as possible. To use convection heat transfer which is the cross sectional area of the copper thickness and width.

A good source for PCB thermal design is Texas Instruments Application Note 2020 Thermal Design By Insight, Not Hindsight

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Misunderstood
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To see how surface area can be used for convective cooling see Section 3.1.1 Example: Calculating the Required Board Size to Hit a Target θJA, in the thermal design reference below.

To see how surface area can be used for convective cooling see Section 3.1.1 Example: Calculating the Required Board Size to Hit a Target θJA in the thermal design reference below.

To see how surface area can be used for convective cooling see Section 3.1.1 Example: Calculating the Required Board Size to Hit a Target θJA, in the thermal design reference below.

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It's not that simple.

First off you do not put the entire thermal load on a linear regulator. You want to reduce PD with a serial power resistor on the supply line. Notice the 0.33Ω resistor on the output of the first LT3033. See page 16 of the datasheet to calculate its value.

to make this example work with the TO-220 package (3C/W junction-case thermal resistance).

The 3°C/W package thermal impedance is used to compare general thermal performance between packages. This characteristic is often abused and misused in heatsink design.

θJC represents the lowest thermal impedance path from the junction of the IC to the outside world. In some cases it is to the top of the package. More often from the junction to the thermal pad.

When the need requires transferring a large heat load the T-220 package is not correct package even though it has the lowest θJC.

Surface mount packages provide the necessary heat sinking by using the heat spreading capabilities of the PC board, copper traces, and planes. Surface mount heat sinks, plated through-holes and solder-filled vias can also spread the heat generated by power devices
- LT3033 datasheet.

The thermal impedance needed for junction to ambient includes the entire thermal path including the solder, thermal vias, copper thickness (internal and external), and copper area. See tables 3-5 for examples of θJA

You cannot just look at the convection characteristics of a heatsink and pick one with the required corresponding heat transfer characteristics.

Heat sink selection must include the thermal resistance from the junction to the attachment point of the heat sink to be effective.

You cannot look at the system thermal dynamics, you must also understand the thermal heat transfer in between system input and output.
The lack of understanding of heat transfer leads to incorrect and inappropriate comments such as this:

30W needs > 30sq in passive surface area or heatsink + cpu fan for both
– Tony Stewart older than dirt

To see how surface area can be used for convective cooling see Section 3.1.1 Example: Calculating the Required Board Size to Hit a Target θJA in the thermal design reference below.

If you actually needed to dissipate 30W, it is not practical using a rule of thumb that applies to much lower power dissipation. It neglects the other rule of thumb that says 4 oz copper should be used for 6+ watt.

The main purpose of a copper plane is to spread the heat transferring the heat from the junction to ambient as quickly as possible. To use convection heat transfer which is the cross sectional area of the copper thickness and width.

A good source for PCB thermal design is Texas Instruments Application Note 2020 Thermal Design By Insight, Not Hindsight

It is very unlikely that the conductive capability of a PCB's planar copper cross sectional (copper oz) area would be capable of transferring 30 watts of heat flux. Convection is highly dependent on the difference in temperature between ambient and the surface. When the heat is conducted across the copper plane it creates a temperature gradient where the temperature furthest away from the regulator is too inefficient to be effective for convection heat transfer.

Once you have sufficient exposed copper to attach a heatsink, heatsink selection is more empirical experimentation than thermal calculations.

It is generally recommended to use passive cooling to minimize field failures. A fan can be added to increase thermal performance of the device being cooled. For example I will use a passive heatsink that will prevent LEDs from burning up then add forced convection to improve the temperature sensitive radiant flux.

Heatsink selection is beyond the scope of this site. It is certainly much more complex than the amount of surface area or a single heatsink datasheet characteristic.

For example in natural convection the principles of velocity boundary layer development on vertical plates in air is an entire physics discipline. The distance between fins is very important, e.g.: C.W. Leung, S.D. Probert, M.J. Shilston, Heat exchanger: optimal separation for vertical rectangular fins protruding from a vertical rectangular base, Appl. Energy 19 (1985) 77−85.

I would recommend HeatSinkCalculator.com for help in choosing a heat sink. They offer a limited free account.

An inexpensive source of extruded heat sinks is heatsinkusa.com. Consider using the width of the heat sink as the length and get the least expensive one inch length. For example I will buy a one inch length their 12" wide heat sink for a 12" long strip of LEDs.